1

我有如下选择语句和示例输出：-

select uph.creation_date, p.name,p.product_id from product p 
                left join user_product_history uph on p.product_id = uph.product_id 
                where uph.user_id = 124 order by uph.creation_date desc

在此处输入图像描述

如何按具有最新创建日期的产品 ID 分组？请帮忙。谢谢你。

使用 PHP API .model 文件编辑

// ~/user/product_history
    public function product_history($data) {
        $sql = 'select uph.creation_date,
        p.name,
        p.product_id
        from product p
        join user_product_history uph
        on p.product_id = uph.product_id and
        uph.user_id = ?
        join (select product_id,
              MAX(creation_date) AS max_creation_date
              from user_product_history
              where user_id = ?
              group by product_id) dt
        on dt.product_id = uph.product_id and
        dt.max_creation_date = uph.creation_date
        order by uph.creation_date desc';

        $result = $this->db->query($sql, array($data['user_id']));
        $records = array();
        foreach( $result->result_array() as $r ) {
            $r['product_id'] = (int) $r['product_id'];
            $r['sub_category_id'] = (int) $r['sub_category_id'];
            $r['merchant_id'] = (int) $r['merchant_id'];
            if (!isset($r['price_discount'])) $r['price_discount'] = '';
            $records[] = $r;
        }
        return $records;
    }
4

2 回答 2

3
  • 首先，您不需要在Left Join这里，因为您也在user_product_history表格上进行过滤。似乎您只想显示那些creation_date对应于 的产品user_id = 124。因此，您可以简单地使用Inner Join。
  • creation_date在派生表（子选择查询）中，确定每个的最大值product_id。
  • 现在，使用此结果集连接到主表 onproduct_id和 thecreation_date以获取完整的行。

尝试以下操作：

select uph.creation_date, 
       p.name,
       p.product_id 
from product p 
join user_product_history uph 
  on p.product_id = uph.product_id and 
     uph.user_id = 124 
join (select product_id, 
             MAX(creation_date) AS max_creation_date
      from user_product_history 
      where user_id = 124 
      group by product_id) dt 
  on dt.product_id = uph.product_id and 
     dt.max_creation_date = uph.creation_date 
order by uph.creation_date desc
于 2018-11-05T04:09:24.947 回答
0 
select 
    uph.creation_date, 
    p.name,p.product_id 
from 
    product p 
    left join user_product_history uph on p.product_id = uph.product_id 
where 
    uph.user_id = 124 and
    uph.creation_date = (select
                             max(creation_date)
                         from 
                             user_product_history) 
order by 
    uph.creation_date desc
于 2018-11-05T04:02:51.540 回答