我使用类似下面的代码来解决这个问题,monitorFiles(...) 方法在应用程序初始化时被调用,它监视文件,当它看到变化时发送 TERM 信号。
我仍然更喜欢使用 paster 的 --reload 参数的解决方案,因为我认为这个解决方案有错误:
import os
import time
import signal
from deepthought.system import deployment
from multiprocessing.process import Process
def monitorFiles():
if deployment.getDeployment().dev and not FileMonitor.isRunning:
monitor = FileMonitor(os.getpid())
try: monitor.start()
except: print "Something went wrong..."
class FileMonitor(Process):
isRunning = False
def __init__(self, masterPid):
self.updates = {}
self.rootDir = deployment.rootDir() + "/src/python"
self.skip = len(self.rootDir)
self.masterPid = masterPid
FileMonitor.isRunning = True
Process.__init__(self)
def run(self):
while True:
self._loop()
time.sleep(5)
def _loop(self):
for root, _, files in os.walk(self.rootDir):
for file in files:
if file.endswith(".py"):
self._monitorFile(root, file)
def _monitorFile(self, root, file):
mtime = os.path.getmtime("%s/%s" % (root, file))
moduleName = "%s/%s" % (root[self.skip+1:], file[:-3])
moduleName = moduleName.replace("/",".")
if not moduleName in self.updates:
self.updates[moduleName] = mtime
elif self.updates[moduleName] < mtime:
print "Change detected in %s" % moduleName
self._restartWorker()
self.updates[moduleName] = mtime
def _restartWorker(self):
os.kill(self.masterPid, signal.SIGTERM)