我有 2 个表格(Form1 和 Form2)。Form1 有一个带有两个面板的拆分器。我在拆分器控件的 panel2 中添加了 Form2。我想在不创建 Form2 的新实例的情况下弹出和弹出 Form2。请在下面找到代码片段:
public partial class Form1 : Form
{
private Form2 form2 = null;
public Form1()
{
InitializeComponent();
}
private void Form1_Load(object sender, EventArgs e)
{
form2 = new Form2();
form2.FormBorderStyle = System.Windows.Forms.FormBorderStyle.None;
form2.Dock = DockStyle.Fill;
form2.TopLevel = false;
splitContainer1.Panel2.Controls.Add(form2);
form2.Pop += new EventHandler(PopForm);
form2.Show();
}
//button click event handler from Form2
private void PopForm(object sender, EventArgs e)
{
Button b = sender as Button;
if(b.Text.ToUpper() == "POPOUT")
{
splitContainer1.Panel2Collapsed = true;
splitContainer1.Panel2.Controls.Remove(form2);
//need to show the form without creating a new instance to maintain state
form2 = new Form2();
form2.SelectedMailId = 1;
form2.Pop += new EventHandler(PopForm);
form2.SetButtonText = "PopIn";
form2.Show();
}
else
{
//this works fine
splitContainer1.Panel2Collapsed = false;
form2.FormBorderStyle = System.Windows.Forms.FormBorderStyle.None;
form2.Dock = DockStyle.Fill;
form2.TopLevel = false;
splitContainer1.Panel2.Controls.Add(form2);
}
}
}
弹出时如何在不创建新实例的情况下显示 Form2?