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在这里实现我的目标可能有许多更直接的方法，但作为一个 Python 新手，如果我们能专注于我正在使用的代码，我将不胜感激。我正在尝试使用 Python 3.6.4（操作系统：Windows 10 Pro）为图形程序（G'MIC）写出命令列表并将其输出到命令提示符（尽管不是直接），我需要写很多代码行，但每一行必须有不同的数字集（整数和浮点数）..例如在我现在尝试使用的代码中，语法是这样的：

gmic v -99 input_.png fx_pastell 
0.5,1,0,10,40,633,11,95,1,1,0.291651967558584,0,0,8,150,1,81,1,0,0,0 -o 
out_001.png

^ 所有变量都表示特定脚本中的参数（在本例中为 Pastell 效果）。

我编写的代码依赖于 Random 模块来获取我想要更改的每个参数范围内的某些数字。我的绊脚石是让脚本在每次打印一行时输出不同的随机数。这是我的代码（这很糟糕，我知道..）：

import random

a = random.randint (3,13)
b = random.randint (1,68)
c = random.randint (1,682)
d = random.randint (2,12)
e = random.randint (1,109)
g = random.randint (1,8)
h = random.uniform (0, 1)
k = random.randint (1,11)
l = random.randint (1,201)
n = random.randint (1,300)
o = random.randint (1,4)

dataFile = open("gmic1.txt", "w")
for line in range(120):
    dataFile.write("gmic v -99 input_.png fx_pastell 0.5,1,0" + "," + str(a) 
+ "," + str(b) + "," + str(c) + "," +str(d) + "," + str(e) + ",1," + str(g) 
+ "," + str(h) + ",0,0," + str(k) + "," + str(l) + ",1,"  + str(n) + "," + 
str(o) +"," + "0,0,0 -o out_%04d.png \n" % line)

dataFile.close()

输出是这样的：

gmic v -99 input_.png fx_pastell 
0.5,1,0,12,2,521,12,85,1,7,0.04003331068764937,0,0,8,17,1,297,2,0,0,0 -o 
out_0000.png 
gmic v -99 input_.png fx_pastell 
0.5,1,0,12,2,521,12,85,1,7,0.04003331068764937,0,0,8,17,1,297,2,0,0,0 -o 
out_0001.png 

.. etc...

没有这样的错误，但没有像我希望的那样每次输出一组不同的数字。

我可以使用 Notepad++ 的列编辑器更改第一个输入图像名称变量，这样就可以解决这个问题，我只需要知道如何使每一行代码都不同。

非常感谢任何帮助！

4

1 回答 1

1

您应该在每次迭代时调用 rand 函数

from random import randint, uniform

dataFile = open("gmic1.txt", "w")
for line in range(120):
    dataFile.write("gmic v -99 input_.png fx_pastell 0.5,1,0"
                   + "," + str(randint(3, 13))
                   + "," + str(randint(1, 68))
                   + "," + str(randint(1, 682))
                   + "," + str(randint(2, 12))
                   + "," + str(randint(1, 109))
                   + ",1," + str(randint(1, 8))
                   + "," + str(uniform(0, 1))
                   + ",0,0," + str(randint(1, 11))
                   + "," + str(randint(1, 201))
                   + ",1," + str(randint(1, 300))
                   + "," + str(randint(1, 4))
                   + "," + "0,0,0 -o out_%04d.png \n" % line)
dataFile.close()
于 2018-10-25T14:57:49.113 回答