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我想创建一个用于测试目的的数据子集，我从一个用户表开始，选择 a 类型的 X、b 类型的 Y、c 类型的 Z（等等），然后创建一个包含这些的新表用户。然后我需要创建所有相关表（带有必要的记录），然后创建所有相关表...

我相当确定最好的方法是递归公用表表达式，但是我对这些没有太多经验，希望有人能帮助我。到目前为止，我有以下内容，但注意到两件事：

  1. 2 级似乎包含了 1 级中的所有内容，除了我期望的新记录

  2. 这实际上并没有创建/插入记录（我仍然需要帮助）

    WITH cte AS
(
    SELECT DISTINCT fk.object_id, fk.schema_id, fk.parent_object_id, fc.parent_column_id, t.schema_id AS referenced_schema_id, fk.referenced_object_id, ic.column_id AS referenced_column_id, 1 AS Level
    FROM sys.foreign_keys fk
        INNER JOIN sys.tables t ON fk.referenced_object_id = t.object_id
        INNER JOIN sys.foreign_key_columns fc ON fk.object_id = fc.constraint_object_id
        INNER JOIN sys.indexes i ON fk.referenced_object_id = i.object_id AND i.is_primary_key = 1
        INNER JOIN sys.index_columns ic ON i.object_id = ic.object_id AND i.index_id = ic.index_id
    WHERE fk.type = 'F' 
        AND fk.referenced_object_id = OBJECT_ID(N'dbo.Users', N'U')

    UNION ALL

    SELECT fk.object_id, fk.schema_id, fk.parent_object_id, fc.parent_column_id, t.schema_id, fk.referenced_object_id, ic.column_id AS referenced_column_id, cte.Level + 1
    FROM sys.foreign_keys fk     
        INNER JOIN sys.tables t ON fk.referenced_object_id = t.object_id
        INNER JOIN sys.foreign_key_columns fc ON fk.object_id = fc.constraint_object_id
        INNER JOIN sys.indexes i ON fk.referenced_object_id = i.object_id AND i.is_primary_key = 1
        INNER JOIN sys.index_columns ic ON i.object_id = ic.object_id AND i.index_id = ic.index_id
        INNER JOIN cte ON fk.referenced_object_id = cte.parent_object_id
    WHERE fk.type = 'F' 
        AND fk.parent_object_id <> cte.referenced_object_id
),
cteHierarchy AS (
    SELECT DISTINCT
        OBJECT_NAME(cte.object_id) AS ReferringKey,
        SCHEMA_NAME(cte.schema_id) AS ReferringSchema,
        OBJECT_NAME(cte.parent_object_id) as ReferringTable,
        COL_NAME(cte.parent_object_id,cte.parent_column_id) ReferringColumn,
        SCHEMA_NAME(cte.referenced_schema_id) AS ReferencedSchema,
        OBJECT_NAME(cte.referenced_object_id) as ReferencedTable,
        COL_NAME(cte.referenced_object_id,cte.referenced_column_id) ReferencedColumn,
        Level
    FROM cte
)
SELECT *
FROM cteHierarchy
ORDER BY Level, ReferencedSchema, ReferencedTable, ReferringTable;

谢谢您的帮助！

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0 回答 0