-1

In python is it possible to compare all objects in the following structure

I have a dictionary of lists and each list has objects in it e.g.

[
      [object1,object2,object3],
      [object4,object5,object6],
      [object7,object8,object9],
]

I want to compare all objects by a attribute in each list to each other and identify what objects are not in each list.

Based on the feedback please see an example below

from collections import defaultdict
from pprint import pprint

class mytest:
  def __init__(self, no, description):
    self.no = no
    self.description = description

data = []


x = mytest(1,'test1')
x2 = mytest(2,'test1')

x3 = mytest(1,'test2')
x4 = mytest(2,'test2')
x5 = mytest(3,'test2')


x6 = mytest(1,'test3')
x7 = mytest(2,'test3')
x8 = mytest(4,'test3')


data.append(x)
data.append(x2)
data.append(x3)
data.append(x4)
data.append(x5)
data.append(x6)
data.append(x7)
data.append(x8)


groups = defaultdict(list)

for obj in data:
    groups[obj.description].append(obj)

new_list = groups.values()


#i want to find out what items are not in each list
for list in new_list:
    pprint(list)


#example x8 = mytest(4,'test3') is only in one of the list so is missing from list 1 and 2

hopefully this helps

4

1 回答 1

1

我想这就是你要找的。我们创建一组可能的值，obj.no然后使用集合差异运算符（-在两个集合上使用，以获取缺失的元素）。

# Get a set of all the no. values present in the data.
combined_set_of_values = set([item.no for item in data])

# Get the sets of obj.no values grouped by description.
for obj in data:
    groups[obj.description].append(obj.no)

new_list = groups.values()


# Print the list, and the elements missing from that list
for list in new_list:
    print("Values in list:")
    print(list)
    # Use set difference to see what's missing from list.
    print("Missing from list:")
    print(combined_set_of_values - set(list))

这给出了以下输出：

Values in list:
[1, 2]
Missing from list:
{3, 4}
Values in list:
[1, 2, 3]
Missing from list:
{4}
Values in list:
[1, 2, 4]
Missing from list:
{3}
于 2018-10-17T14:20:36.327 回答