mqtt - MQTT 使用 URL HIVEMQ 发布

Question

如何使用 URL 发布到 MQTT 主题。

即“ http://127.0.0.1/cmnd/power/on ”将“ on ”发送到“ power ”主题。

ps：我正在使用 HiveMQ

Answer 1

MQTT 通常使用 TCP 作为底层协议（HTTP 仅在 websocket 上下文中）。

使用 paho mqtt 客户端库连接 mqtt 客户端的 Java 示例：

import org.eclipse.paho.client.mqttv3.*;
import org.eclipse.paho.client.mqttv3.persist.MemoryPersistence;
...

final MqttClient mqttClient = new MqttClient("tcp://localhost:1883", 
      MqttClient.generateClientId(), 
      new MemoryPersistence());  
opt.setUserName("User");
...
mqttClient.connect(opt);
...

//subscribe to all topics 
mqttClient.subscribe("#");

//publish your status ON with a QoS 1 message that is retained 
mqttClient.publish("cmnd/power, ("on").getBytes(), 1, true);

Answer 2

首先，您需要建立 mqtt 连接，一旦连接成功，您就可以将任何有效负载发送到所需的主题。这就是您需要启动连接的方式。

 String clientId = MqttClient.generateClientId();
 MqttConnectOptions options = new MqttConnectOptions();
 options.setUserName("USERNAME");
 options.setPassword("PASSWORD".toCharArray());
 MqttAndroidClient client =
    new MqttAndroidClient(this.getApplicationContext(), "tcp://broker.hivemq.com:1883",
                          clientId);

  try {
       IMqttToken token = client.connect(options);
       token.setActionCallback(new IMqttActionListener() {
       @Override
        public void onSuccess(IMqttToken asyncActionToken) {
        // We are connected
        Log.d(TAG, "onSuccess");
       }

      @Override
      public void onFailure(IMqttToken asyncActionToken, Throwable exception) {
        // Something went wrong e.g. connection timeout or firewall problems
        Log.d(TAG, "onFailure");
       }
      });
     } catch (MqttException e) {
    e.printStackTrace();
 }

You can publish message to topic power 


     String topic = "power";
     String payload = "ON";
     byte[] encodedPayload = new byte[0];

   try {
       encodedPayload = payload.getBytes("UTF-8");
       MqttMessage message = new MqttMessage(encodedPayload);
       client.publish(topic, message);
     }  catch (UnsupportedEncodingException | MqttException e) {
      e.printStackTrace();
   }