嘿伙计们,我刚开始学习 React 本机上下文 api 我想知道我如何才能像全局状态一样在全局范围内实现它,并且在导航到另一个屏幕后它也不起作用,为什么我们在提供程序中包含类名<ProfileScreen screen= {this.state.contextData}/>
我们可以在全局范围内实现吗..这是我的代码
global.cart=1
const Context = React.createContext(global.cart)
class HomeScreen extends Component<Props> {
constructor(props){
super(props);
this.state={
contextData:5
}
}
Incrementhome=()=>{
this.setState({contextData:global.cart})
global.cart++
}
Decrementhome=()=>{
this.setState({contextData:global.cart})
global.cart--
}
render() {
return (
<View>
<Context.Provider value={this.state.contextData}>
<Button title="Incrementhome"
onPress={this.Incrementhome}/>
<Button title="decrementhome"
onPress={this.Decrementhome}/>
<ProfileScreen screen= {this.state.contextData}/>
</Context.Provider>
<Button title='sd' onPress={()=>{this.props.navigation.navigate('Profile')}}/>
</View>
)
}
}
可以显示我的数据的班级资料屏幕
class ProfileScreen extends Component<Props> {
render() {
return (
<View style={{}}>
<Context.Consumer>
{data=> <Text style={{fontSize:50}}>{data}</Text>}
</Context.Consumer>
</View>
);
}
}
类配置文件屏幕也是提供者
class ProfileScreens extends Component<Props> {
static navigationOptions =
{
title: 'MainActivity', header: <Button title='sd' onPress={()=>{this.props.navigation.navigate('ProfileScreen')}}/>
};
constructor(props){
super(props);
this.state={contextData:0
}
}
render() {
return (
<View >
<Context.Provider value={this.state.contextData}>
<Button title="decrement" onPress={()=>{ this.props.changeHomeScreen() }}/>
<Button title='sd' onPress={()=>{this.props.navigation.navigate(Profile)}}/>
</Context.Provider>
</View>
);
}
}
我的导航器
export default HomeScreen = createStackNavigator({
HomeScreen:{
screen:HomeScreen
},
Profile:{
screen:ProfileScreen
},
ProfileScreens:{
screen:ProfileScreens
},
})