5

我想打印以毫秒为单位的持续时间,并根据其大小使用不同的格式规范:

case (1)      "H:mm"  if duration < 10 hours
case (2)     "HH:mm"  if duration < 24 hours
case (3)  "#d HH:mm"  else (duration >= 24 hours)

这意味着持续时间低于 10 小时的只有 1 小时字段数字,
但有前导日字段时只有 2 小时字段数字!

例子:

case (1)      "0:45"  means 45 minutes,
              "1:23"  means 1 hour and 23 minutes,
case (2)     "12:05"  means 12 hours and 5 minutes and
case (3)  "1d 05:09"  means 1 day, 5 hours and 9 minutes
                               (= 29 hours and 9 minutes).

我试过

object JodaTest {
  import org.joda.time._
  private val pdf = {
    import format._
    val pfb = new PeriodFormatterBuilder()
      .appendDays.appendSeparator("d ")
      .printZeroAlways
      .minimumPrintedDigits(2).appendHours.appendSeparator(":")
      .appendMinutes
    new PeriodFormatter(pfb.toPrinter, null)
  }
  def durstr(duration: Long): String =
    pdf.print((new Period(duration)).normalizedStandard)
}

这导致

  2700000 => "00:45"     but should be "0:45"
  4980000 => "01:23"     but should be "1:23"
 43500000 => "12:05"
104940000 => "1d 05:09"

但我不知道如何在情况(1)中省略两位数日表示的前导零,但同时强制在情况(3)中使用相同的 PeriodFormat 打印它。

有没有可能用一个来做到这一点org.joda.time.format.PeriodFormatter

4

3 回答 3

1

也许不是一个真正的答案,但同时我担心你需要两个 PeriodFormatter来解决这个任务,所以管理它

object JodaTest {
  import org.joda.time._
  import format._
  private def pdf(digits: Int) = new PeriodFormatter(
    new PeriodFormatterBuilder()
      .appendDays.appendSeparator("d ")
      .printZeroAlways
      .minimumPrintedDigits(digits).appendHours.appendSeparator(":")
      .minimumPrintedDigits(2).appendMinutes
      .toPrinter, null)
  private lazy val pdf1 = pdf(1)
  private lazy val pdf2 = pdf(2)
  def durstr(duration: Long): String = {
    val period = new Period(duration).normalizedStandard
    val pdf = if (period.getDays > 0) pdf2 else pdf1
    pdf.print(period)
  }
}

这导致想要的

  2700000 => "0:45"
  4980000 => "1:23"
 43500000 => "12:05"
104940000 => "1d 05:09".
于 2011-03-11T16:16:53.890 回答
0

仍然找到了一个只有一个 PeriodFormatter但在 Joda-Time 之外做一些工作的解决方案。

这个想法是

  1. 使用 Joda-Time 和
  2. 分别删除不需要的前导零

object JodaTest {
  import org.joda.time._
  import format._
  // "000d 00:00" - 3 day digits for periods with up to 999 days long
  private val pdf = new PeriodFormatter(new PeriodFormatterBuilder()
    .printZeroAlways
    .minimumPrintedDigits(3).appendDays.appendSeparator("d ")
    .minimumPrintedDigits(2).appendHours.appendSeparator(":").appendMinutes
    .toPrinter, null)
  private def adjust(rawstr: String): String = {
    // "000d 00:00" => ("000d 0", "0:00")
    val (first, second) = rawstr splitAt 6
    // remove unwanted leading zeros in first part, keep it in second
    first.dropWhile(c => !c.isDigit || c == '0') + second
  }
  def durstr(duration: Long): String = {
    // PeriodType.dayTime => day is the most significant field (no weeks etc.)
    adjust(pdf.print(new Period(duration) normalizedStandard PeriodType.dayTime))
  }
}

这导致

   duration =>       rawstr =>       adjust
          0 => "000d 00:00" =>       "0:00"
    2700000 => "000d 00:45" =>       "0:45"
    4980000 => "000d 01:23" =>       "1:23"
   43500000 => "000d 12:05" =>      "12:05"
  104940000 => "001d 05:09" =>   "1d 05:09"
  518760000 => "006d 00:06" =>   "6d 00:06"
  605220000 => "007d 00:07" =>   "7d 00:07"
  951060000 => "011d 00:11" =>  "11d 00:11"
43230000000 => "500d 08:20" => "500d 08:20"

当然,最好直接使用 Joda-Time 构建此类格式,方法是指定 Excel 数字格式 (#,##0.00#) 之类的模式来说明在哪里需要零或仅在需要时使用。但似乎不清楚如何准确定义它,因为您不仅有“0”和“#”,而且每个字段都需要字符并将文字放入格式字符串(可能通过转义)也会很好。

于 2011-03-13T20:38:23.867 回答
0

您可以实现PeriodPrinter接口以完全按照您的意愿格式化句点,然后使用构建器设置格式化程序。

于 2011-03-22T07:47:48.220 回答