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我正在尝试使用 azure sdk 创建服务主体。但是,我收到一个错误

{"odata.error":{"code":"Authorization_RequestDenied","message":{"lang":"en","value":"Insufficient privileges to complete the operation."}}}

我究竟做错了什么?我正在执行以下操作:

  1. 创建具有所有者角色的服务主体

    az ad sp create-for-rbac -n "OrbitTest5" --role Owner --sdk-auth
    
  2. 通过环境变量将创建的服务主体的凭据传递给凭据提供程序

    public class AzureAppEnvCredentialProvider implements AzureCredentialProvider {
      public static final String ENV_CLIENT_ID = "CLIENT_ID";
      public static final String ENV_TENANT_ID = "TENANT_ID";
      public static final String ENV_SUBSCRIPTION_ID = "SUBSCRIPTION_ID";
      public static final String ENV_CLIENT_SECRET = "CLIENT_SECRET";
    
      private final String subscriptionId;
    
      public AzureAppEnvCredentialProvider() {
        this.subscriptionId = Preconditions.checkNotNull(System.getenv(ENV_SUBSCRIPTION_ID));
      }
    
      @Override
      public AzureTokenCredentials getCredentials() {
        final String clientId = Preconditions.checkNotNull(System.getenv(ENV_CLIENT_ID));
        final String tenantId = Preconditions.checkNotNull(System.getenv(ENV_TENANT_ID));
        final String clientSecret = Preconditions.checkNotNull(System.getenv(ENV_CLIENT_SECRET));
        return new ApplicationTokenCredentials(clientId, tenantId, clientSecret, AzureEnvironment.AZURE);
      }
    
      @Override
      public String getSubscriptionId() {
        return this.subscriptionId;
      }
    }
    
  3. 使用凭证通过 java sdk 创建服务主体

        azureAuthClient = Azure.configure().authenticate(credentialProvider.getCredentials());
    
        final ServicePrincipal servicePrincipal = 
            azureAuthClient.servicePrincipals()
            .define(clusterId)
            .withNewApplication("http://easycreate.azure.com/" + clusterId)
              .definePasswordCredential("sppass")
              .withPasswordValue("StrongPass!12")
              .attach()
            .create();
    
  4. 然后我得到一个例外。我知道我的凭据有效,因为我能够使用 sdk 创建资源组并从 Azure Web 控制台查看它。

    com.microsoft.azure.management.graphrbac.GraphErrorException: 状态码 403,{"odata.error":{"code":"Authorization_RequestDenied","message":{"lang":"en","value":"权限不足,无法完成操作。"}}} 在 sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method) 在 sun.reflect.NativeConstructorAccessorImpl.newInstance(NativeConstructorAccessorImpl.java:62) 在 sun.reflect.DelegatingConstructorAccessorImpl.newInstance(DelegatingConstructorAccessorImpl.java :45) 在 java.lang.reflect.Constructor.newInstance(Constructor.java:423) 在 com.microsoft.rest.ServiceResponseBuilder.build(ServiceResponseBuilder.java:122) 在 com.microsoft.azure.AzureResponseBuilder.build(AzureResponseBuilder. java:56) 在 com.microsoft.azure.management.graphrbac。implementation.ApplicationsInner.createDelegate(ApplicationsInner.java:194) 在 com.microsoft.azure.management.graphrbac.implementation.ApplicationsInner.access$000(ApplicationsInner.java:45) 在 com.microsoft.azure.management.graphrbac.implementation.ApplicationsInner $2.call(ApplicationsInner.java:181) at com.microsoft.azure.management.graphrbac.implementation.ApplicationsInner$2.call(ApplicationsInner.java:177) at rx.internal.operators.OnSubscribeMap$MapSubscriber.onNext(OnSubscribeMap.java :69) 在retrofit2.adapter.rxjava.CallArbiter.deliverResponse(CallArbiter.java:120) 在retrofit2.adapter.rxjava.CallArbiter.emitResponse(CallArbiter.java:102) 在retrofit2.adapter.rxjava.CallExecuteOnSubscribe.call(CallExecuteOnSubscribe。 java:46) 在retrofit2.adapter.rxjava.CallExecuteOnSubscribe.call(CallExecuteOnSubscribe.java:24) 在rx.Observable。unsafeSubscribe(Observable.java:10327) 在 rx.internal.operators.OnSubscribeMap.call(OnSubscribeMap.java:48) 在 rx.internal.operators.OnSubscribeMap.call(OnSubscribeMap.java:33) 在 rx.internal.operators.OnSubscribeLift .call(OnSubscribeLift.java:48) 在 rx.internal.operators.OnSubscribeLift.call(OnSubscribeLift.java:30) 在 rx.Observable.unsafeSubscribe(Observable.java:10327) 在 rx.internal.operators.OnSubscribeMap.call( OnSubscribeMap.java:48) 在 rx.internal.operators.OnSubscribeMap.call(OnSubscribeMap.java:33) 在 rx.Observable.unsafeSubscribe(Observable.java:10327) 在 rx.internal.operators.OnSubscribeMap.call(OnSubscribeMap.java :48) 在 rx.internal.operators.OnSubscribeMap.call(OnSubscribeMap.java:48) 的 rx.Observable.unsafeSubscribe(Observable.java:10327) 的 rx.internal.operators.OnSubscribeMap.call(OnSubscribeMap.java:33)在 rx.internal.operators。OnSubscribeMap.call(OnSubscribeMap.java:33) 在 rx.internal.operators.OnSubscribeLift.call(OnSubscribeLift.java:48) 在 rx.internal.operators.OnSubscribeLift.call(OnSubscribeLift.java:30) 在 rx.Observable.unsafeSubscribe (Observable.java:10327) 在 rx.internal.operators.OperatorSubscribeOn$SubscribeOnSubscriber.call(OperatorSubscribeOn.java:100) 在 rx.internal.schedulers.CachedThreadScheduler$EventLoopWorker$1.call(CachedThreadScheduler.java:230) 在 rx.internal .schedulers.ScheduledAction.run(ScheduledAction.java:55) 在 java.util.concurrent.Executors$RunnableAdapter.call(Executors.java:511) 在 java.util.concurrent.FutureTask.run(FutureTask.java:266) 在java.util.concurrent.ScheduledThreadPoolExecutor$ScheduledFutureTask.access$201(ScheduledThreadPoolExecutor.java:180) 在 java.util.concurrent.ScheduledThreadPoolExecutor$ScheduledFutureTask。在 java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:624) 在 java.lang.Thread 的 java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1149) 运行(ScheduledThreadPoolExecutor.java:293) .run(Thread.java:748)

4

1 回答 1

1

正如我提到的,如果我们想创建 servicePrincipal 那么资源应该是http://graph.windows.netor https://graph.microsoft.com

所以我们需要添加操作 Azure AD Graph API 或 Microsoft Graph API 的权限。

别忘了Grant permission

我使用 Azure Active Directory API 对其进行测试。我在我身边工作正常。

演示代码:

ApplicationTokenCredentials credentials = new ApplicationTokenCredentials(client,
               tenant,
                key,
                AzureEnvironment.AZURE);

Azure.Authenticated azureAuthClient = Azure.configure().authenticate(credentials);
String clusterId = "xxxxxxx";
ServicePrincipal servicePrincipal =
                azureAuthClient.servicePrincipals()
                        .define(clusterId)
                        .withNewApplication("http://easycreate.azure.com/" + clusterId)
                        .definePasswordCredential("sppass")
                        .withPasswordValue("StrongPass!12")
                        .attach()
                        .create();

在此处输入图像描述

于 2018-10-10T02:48:30.613 回答