mysql - 选择MySQL中不包含某列的表

Question

我正在尝试选择所有没有名为“唯一”的列的表。我可以选择使用它的所有表：

SELECT DISTINCT TABLE_NAME 
FROM INFORMATION_SCHEMA.COLUMNS
WHERE COLUMN_NAME = 'unique'
AND TABLE_SCHEMA ='database';

有没有一种简单的方法来修改 SELECT 语句，以便列出所有没有该列的表？这似乎很简单，但我无法弄清楚，也无法在论坛上找到答案。

谢谢

Answer 1

select
t.*
from INFORMATION_SCHEMA.TABLES as t
    left join INFORMATION_SCHEMA.COLUMNS as c
    on c.TABLE_NAME = t.TABLE_NAME
    and c.TABLE_SCHEMA = t.TABLE_SCHEMA
    and c.COLUMN_NAME = 'unique'
where c.COLUMN_NAME is null
and t.TABLE_SCHEMA = 'database'

Answer 2

如果服务器中仅存在一个数据库，则上述查询有效。如果没有，也会列出来自其他数据库的表。考虑这个从特定数据库中挑选表的简化版本。总而言之，这是一个很大的亮点！

SELECT DISTINCT TABLE_NAME 
FROM INFORMATION_SCHEMA.TABLES 
WHERE TABLE_SCHEMA = 'DATABASE_NAME' 
AND TABLE_NAME NOT IN (SELECT DISTINCT TABLE_NAME 
                            FROM INFORMATION_SCHEMA.COLUMNS 
                           WHERE COLUMN_NAME = 'FIELD_NAME' 
                             AND TABLE_SCHEMA ='DATABASE_NAME');

Answer 3

SELECT TABLE_NAME
FROM INFORMATION_SCHEMA.TABLES
WHERE TABLE_NAME NOT IN (
SELECT DISTINCT TABLE_NAME 
FROM INFORMATION_SCHEMA.COLUMNS
WHERE COLUMN_NAME = 'unique'
AND TABLE_SCHEMA ='database')

Answer 4

一个简单的反转：

SELECT TABLE_NAME
FROM INFORMATION_SCHEMA.TABLES
WHERE TABLE_NAME NOT IN

(SELECT DISTINCT TABLE_NAME 
FROM INFORMATION_SCHEMA.COLUMNS
WHERE COLUMN_NAME = 'unique'
AND TABLE_SCHEMA ='database');