我正在使用 SwiftType Elastic Search + C# 并遇到反序列化响应的问题,因为 SwiftType 将所有字段作为具有raw
属性的对象返回(https://swiftype.com/documentation/app-search/api /搜索)例如:
{
"meta": {
"warnings": [],
"page": {
"current": 1,
"total_pages": 1,
"total_results": 2,
"size": 10
},
"request_id": "6887a53f701a59574a0f3a7012e01aa8"
},
"results": [
{
"phone": {
"raw": 3148304280.0
},
"accounts_balance_ach": {
"raw": 27068128.71
},
"accounts_balance_pending": {
"raw": "46809195.64"
},
"email": {
"raw": "Brisa34@hotmail.com"
},
"accounts_count": {
"raw": 6.0
},
"id": {
"raw": "c98808a2-d7d6-4444-834d-2fe4f6858f6b"
},
"display_name": {
"raw": "The Johnstons"
},
"type": {
"raw": "Couple"
},
"advisor_email": {
"raw": "Cornelius_Schiller14@hotmail.com"
},
"created_at": {
"raw": "2018-10-02T10:42:07+00:00"
},
"source": {
"raw": "event"
},
"accounts_balance": {
"raw": 43629003.47
},
"accounts_donations": {
"raw": 38012278.75
},
"advisor_name": {
"raw": "Cloyd Jakubowski"
},
"_meta": {
"score": 0.42934617
}
},
{
"phone": {
"raw": 2272918612.0
},
"accounts_balance_ach": {
"raw": 35721452.35
},
"accounts_balance_pending": {
"raw": "35117465.2"
},
"email": {
"raw": "Ruby87@yahoo.com"
},
"accounts_count": {
"raw": 1.0
},
"id": {
"raw": "687af11f-0f73-4112-879c-1108303cb07a"
},
"display_name": {
"raw": "Kennith Johnston"
},
"type": {
"raw": "Individual"
},
"advisor_email": {
"raw": "Evangeline_Wisoky92@hotmail.com"
},
"created_at": {
"raw": "2018-10-02T16:16:02+00:00"
},
"source": {
"raw": "website"
},
"accounts_balance": {
"raw": 23063874.19
},
"accounts_donations": {
"raw": 33025175.79
},
"advisor_name": {
"raw": "Ernie Mertz"
},
"_meta": {
"score": 0.39096162
}
}
]
}
我需要将每个键映射到它的值,例如 results[0].email = "Brisa34@hotmail.com";
我看到了使用自定义转换器的有前途的选择,但我想确保在采用详细方法之前没有更动态的方法来执行此操作。