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1.以下代码行仅返回最多 30 个提要

siteFeeds = activityService.getSiteFeedEntries("testSite");

2.Below 代码行仅返回最多 30 个提要。

List<ActivityFeedEntity> activityFeedEntities = activityFeedDAO.selectSiteFeedEntries("testSite", 1000);
  1. 我想获取每个用户的所有提要,然后尝试使用“管理员”,但在这里我也无法获得超过 30 个提要

    int skipCount = 0; for(int i =0; i <10; i++) { PagingRequest pagingRequest = new PagingRequest(skipCount, 15); PagingResults<ActivityFeedEntity> activityFeedEntities = activityFeedDAO.selectPagedUserFeedEntries("admin", null, "testSite", false, false, i, pagingRequest); skipCount = skipCount + 15; }

以下是 repository.properties 中设置的值

# Feed max ID range to limit maximum number of entries
activities.feed.max.idRange=1000000
# Feed max size (number of entries)
activities.feed.max.size=200
# Feed max age (eg. 44640 mins => 31 days)
activities.feed.max.ageMins=44640

谁能帮助我如何获取特定露天网站的所有网站提要

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1 回答 1

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我已经用这个场景 sdk2 进行了测试,它给了我 30 多个条目。

List<ActivityFeedEntity> feeds= activityFeedDAO.selectSiteFeedEntries("demo", 100);
System.out.println(feeds.size());
于 2018-10-30T04:16:54.440 回答