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当我尝试从构造函数外部访问 ui 时,我得到一个 SIGSEGV 信号,该错误是在 prepareQuestions 函数底部的 cpp 文件的最后一行引起的

我尝试将其减少到尽可能小的代码:

标题:

#ifndef QUESTIONSDIALOG_H
#define QUESTIONSDIALOG_H

#include <QDialog>
#include <QHash>

#include "question.h"

namespace Ui {
    class QuestionsDialog;
}

class QuestionsDialog : public QDialog
{
    Q_OBJECT

public:
    explicit QuestionsDialog(QWidget *parent = 0);
    ~QuestionsDialog();
    void prepareQuestions(QString category);

private:
    Ui::QuestionsDialog *ui;
    QHash<QString, Question>* questions; //question id + question object
};

#endif // QUESTIONSDIALOG_H

cpp文件:

#include <QtDebug>
#include "questionsdialog.h"
#include "ui_questionsdialog.h"
#include "question.h"

QuestionsDialog::QuestionsDialog(QWidget *parent) :
    QDialog(parent),
    ui(new Ui::QuestionsDialog)
{
    ui->setupUi(this);
    ui->lbl_question1->setText(QString("this is the constructor")); //works
    ui->txt_input1->setText(QString("this is the constructor")); //works
}

QuestionsDialog::~QuestionsDialog()
{
    delete ui;
}

void QuestionsDialog::prepareQuestions(QString category){
    ui->lbl_question1->setText(QString("this is prepareQuestions method")); //doesn't work
//    ui->txt_input1->setText(QString("test1")); //creates an exception (no error message)
}

我主要在哪里建造

QStackedWidget *dialogStack = new QStackedWidget;
dialogStack->addWidget(new LoginDialog());     //index 0
dialogStack->addWidget(new CallDialog());      //index 1
dialogStack->addWidget(new CategoryDialog());  //index 2
dialogStack->addWidget(new QuestionsDialog()); //index 3

dialogStack->setCurrentIndex(0);

我把 QuestionDialog 放在首位:

QStackedWidget* dialogStack = (QStackedWidget*)this->parentWidget();
QuestionsDialog* questionDialog = ((QuestionsDialog*)dialogStack->widget(1));
//set type of call + properties
dialogStack->setCurrentIndex(3);

questionDialog->prepareQuestions(((QToolButton*)obj)->statusTip());

注释错误行时的 gui(请注意更改 lbl_question1 不起作用) http://i77.photobucket.com/albums/j74/bertyhell/gui.png

使用调试器出错:

http://i77.photobucket.com/albums/j74/bertyhell/seg_fault.png

4

1 回答 1

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您使用错误的索引从对话框堆栈中获取 QuestionDialog 对象:

QuestionsDialog* questionDialog = ((QuestionsDialog*)dialogStack->widget(1));

您应该使用“3”而不是“1”。

于 2011-03-09T09:12:06.710 回答