当我尝试从构造函数外部访问 ui 时,我得到一个 SIGSEGV 信号,该错误是在 prepareQuestions 函数底部的 cpp 文件的最后一行引起的
我尝试将其减少到尽可能小的代码:
标题:
#ifndef QUESTIONSDIALOG_H
#define QUESTIONSDIALOG_H
#include <QDialog>
#include <QHash>
#include "question.h"
namespace Ui {
class QuestionsDialog;
}
class QuestionsDialog : public QDialog
{
Q_OBJECT
public:
explicit QuestionsDialog(QWidget *parent = 0);
~QuestionsDialog();
void prepareQuestions(QString category);
private:
Ui::QuestionsDialog *ui;
QHash<QString, Question>* questions; //question id + question object
};
#endif // QUESTIONSDIALOG_H
cpp文件:
#include <QtDebug>
#include "questionsdialog.h"
#include "ui_questionsdialog.h"
#include "question.h"
QuestionsDialog::QuestionsDialog(QWidget *parent) :
QDialog(parent),
ui(new Ui::QuestionsDialog)
{
ui->setupUi(this);
ui->lbl_question1->setText(QString("this is the constructor")); //works
ui->txt_input1->setText(QString("this is the constructor")); //works
}
QuestionsDialog::~QuestionsDialog()
{
delete ui;
}
void QuestionsDialog::prepareQuestions(QString category){
ui->lbl_question1->setText(QString("this is prepareQuestions method")); //doesn't work
// ui->txt_input1->setText(QString("test1")); //creates an exception (no error message)
}
我主要在哪里建造
QStackedWidget *dialogStack = new QStackedWidget;
dialogStack->addWidget(new LoginDialog()); //index 0
dialogStack->addWidget(new CallDialog()); //index 1
dialogStack->addWidget(new CategoryDialog()); //index 2
dialogStack->addWidget(new QuestionsDialog()); //index 3
dialogStack->setCurrentIndex(0);
我把 QuestionDialog 放在首位:
QStackedWidget* dialogStack = (QStackedWidget*)this->parentWidget();
QuestionsDialog* questionDialog = ((QuestionsDialog*)dialogStack->widget(1));
//set type of call + properties
dialogStack->setCurrentIndex(3);
questionDialog->prepareQuestions(((QToolButton*)obj)->statusTip());
注释错误行时的 gui(请注意更改 lbl_question1 不起作用)
使用调试器出错: