我有一个源代码可以打开一个 csv 文件并设置一个值关联的标题。源代码如下:
def ParseCsvFile(source):
"""Parse the csv file.
Args:
source: file to be parsed
Returns: the list of dictionary entities; each dictionary contains
attribute to value mapping or its equivalent.
"""
global rack_file
rack_type_file = None
try:
rack_file = source
rack_type_file = open(rack_file) # Need to mock this line.
headers = rack_type_file.readline().split(',')
length = len(headers)
reader = csv.reader(rack_type_file, delimiter=',')
attributes_list=[] # list of dictionaries.
for line in reader:
# More process to happeng. Converting the rack name to sequence.
attributes_list.append(dict((headers[i],
line[i]) for i in range(length)))
return attributes_list
except IOError, (errno, strerror):
logging.error("I/O error(%s): %s" % (errno, strerror))
except IndexError, (errno, strerror):
logging.error('Index Error(%s), %s' %(errno, strerror))
finally:
rack_type_file.close()
我试图模拟以下语句
rack_type_file = open(rack_file)
如何模拟 open(...) 函数?