1

我RouteConfig在包中创建了一个类，app.config如下所示：

public class RouteConfig extends AbstractRouteConfig {
  @Override
  public void init(AppContext appContext) {

  route("/{controller}/{aut_id}/").to(AuthorsController.class).action("findById");
}

我创建了AppControllerConfig类：

package app.config;

import app.controllers.CatchAllFilter;
import app.controllers.api.v2.AuthorsController;
import org.javalite.activeweb.AbstractControllerConfig;
import org.javalite.activeweb.AppContext;
import org.javalite.activeweb.controller_filters.DBConnectionFilter;

public class AppControllerConfig extends AbstractControllerConfig {

    public void init(AppContext context) {
        add(new DBConnectionFilter(), new CatchAllFilter()).to(AuthorsController.class);
    }
}

我还定义APIController了类如下：

package app.controllers;

import org.javalite.activeweb.AppController;

public abstract class APIController extends AppController {
    @Override
    protected String getContentType() {
        return "application/json";
    }

    @Override
    protected String getLayout() {
        return null;
    }

}

AuthorsControllerapp.controllers.api.v2包装内：

import app.controllers.APIController;

import app.models.Author;

public class AuthorsController extends APIController {

    public void findById() {
        if (blank("aut_id")) {
            throw new RuntimeException("aut_id number is mandatory but was empty or null");
        } else {
            Author author = Author.findById(param("aut_id"));
            String jsonResponse = author.toJson(false);
            respond(jsonResponse);
        }
    }
}

尝试访问 urlhttp://localhost:8080/api/v2/authors/9时，出现错误：

Request properties: Request URL: http://localhost:8080/api/v2/authors/9
ContextPath: 
Query String: null
URI Full Path: /api/v2/authors/9
URI Path: /api/v2/authors/9
Method: GET

Request parameters: {}
Request headers: {Cookie=_ga=GA1.1.1833610632.1527846931; JSESSIONID=node03k88mhw4nihozrzi9ehiiadj0.node0, Cache-Control=no-cache, Accept=text/html,application/xhtml+xml,application/xml;q=0.9,image/webp,image/apng,*/*;q=0.8, Upgrade-Insecure-Requests=1, Connection=keep-alive, User-Agent=Mozilla/5.0 (Macintosh; Intel Mac OS X 10_13_6) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/68.0.3440.106 Safari/537.36, Host=localhost:8080, Pragma=no-cache, Accept-Encoding=gzip, deflate, br, Accept-Language=en,fr;q=0.9,ru;q=0.8}
org.javalite.activeweb.ActionNotFoundException: java.lang.NoSuchMethodException: app.controllers.api.v2.AuthorsController.9(); app.controllers.api.v2.AuthorsController.9()
[qtp1987707214-16] WARN ParamCopy - found 'session' value set by controller. It is reserved by ActiveWeb and will be overwritten.
[qtp1987707214-16] INFO FreeMarkerTemplateManager - rendering template: '/system/404' with layout: '/layouts/default_layout', session: node018slc2f7n5p0v67173ezr8guc0
[qtp1987707214-16] WARN FreeMarkerTemplateManager - Current location: /Users/Serguei/projects/java/newton-interventions
[qtp1987707214-16] ERROR RequestDispatcher - ActiveWeb internal error: 
org.javalite.activeweb.ViewMissingException: Failed to render template: '/system/404.ftl', with layout: '/layouts/default_layout'; Template "/system/404.ftl" not found.

我究竟做错了什么 ？我什至没有输入AuthorsController......它似乎忽略了我的路线定义并试图找到以下路线：

"method":"GET","action":"9","error":"java.lang.NoSuchMethodException: app.controllers.api.v2.AuthorsController.9()

在同一个控制器中声明index动作时，如下所示：

public void index() {
        final String json = Author.findFirst("AUT_ID = 9").toJson(false);
        respond(json);
    }

并击中http://localhost:8080/api/v2/authors，它的工作原理。

4

2 回答 2

1

这刷新了路由系统中的错误：https ://github.com/javalite/activeweb/issues/397 该错误已修复，并将新快照部署到 Sonatype 版本：2.3-SNAPSHOT。 https://oss.sonatype.org/content/repositories/snapshots/org/javalite/activeweb/2.3-SNAPSHOT/

您现在可以尝试看看这是否有效。BWT，感谢您的详细描述，它有助于设置正确的规范： RouterCustomSpec

于 2018-09-17T21:06:09.653 回答
0

最后，我想出了如何让它工作。

我在类中更改了路由声明，RouteConfig如下所示：

route("/{controller}/find-by-id}/{id}").to(AuthorsController.class).action("findById");

我将方法更改findById如下AuthorsController：

public void findById() {
        System.out.println(params());
        if (blank("id")) {
            throw new RuntimeException("autId number is mandatory but was empty or null");
        } else {
            Author author = Author.findById(param("id"));
            String jsonResponse = author.toJson(false);
            respond(jsonResponse);
        }
    }

似乎按照惯例，作为数字传递给 url 的参数名称被认为是id，仅此而已，对吧？

于 2018-09-17T15:12:45.220 回答