0

例如我有:

String templateString = "Hi {{customerName}}, you have successfully ordered a {{itemName}}."
Map<String, String> parameters = new HashMap<>();
parameters.put("customerName", "Bob");
parameters.put("itemName", "sofa");

期望的输出: "Hi Bob, you have successfully ordered a sofa."

获得所需输出的最佳方式(万无一失、可维护、省时等)是什么?

我想做一些简单的事情:

String output = templateString;
for (Map.Entry<String, String> entry : parameters.entrySet()) {
    output = output.replace("{{" + entry.getKey() + "}}", entry.getValue());
}

有没有更好的办法?

4

4 回答 4

1

取决于您需要的模板系统有多复杂。已经有很多了。

两个例子是:

于 2018-09-17T07:04:40.130 回答
0

除了其他答案中已经提供的解决方案外,您还可以使用StringSubstitutorApache Commons Text

来自https://commons.apache.org/proper/commons-text/javadocs/api-release/org/apache/commons/text/StringSubstitutor.html的示例:-

 Map valuesMap = HashMap();
 valuesMap.put("animal", "quick brown fox");
 valuesMap.put("target", "lazy dog");
 String templateString = "The ${animal} jumps over the ${target}.";
 StringSubstitutor sub = new StringSubstitutor(valuesMap);
 String resolvedString = sub.replace(templateString);
于 2018-09-17T23:49:46.403 回答
0

另一种方法是使用Mustache.java, docs

String templateString = "Hi {{customerName}}, you have successfully ordered a {{itemName}}.";
Map<String, String> parameters = new HashMap<>();
parameters.put("customerName", "Bob");
parameters.put("itemName", "sofa");

Writer writer = new StringWriter();
MustacheFactory mf = new DefaultMustacheFactory();
Mustache mustache = mf.compile(new StringReader(templateString), "example");
mustache.execute(writer, parameters);
writer.flush();
System.out.println(writer.toString());
于 2018-09-17T07:26:14.563 回答
0

使用 Map 中的键获取值会更好

            String output = templateString;
            output = output.replace("{{customerName}}",parameters.get("customerName"));
            output = output.replace("{{itemName}}",parameters.get("itemName"));
于 2018-09-17T07:27:19.653 回答