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我正在构建一个使用用户输入并显示食谱数量的应用程序，他们也可以单击食谱卡来查看成分。每次他们点击配方卡时，我都会调用 API 来获取合适的配方成分。但我无法弄清楚如何显示包含配方成分的组件。我也尝试了条件路由和条件渲染，但找不到解决方案。

Recipe_Template.js

  export class RecipeTemplate extends Component {
  renderRecipe = recipeData => {
    return recipeData.recipes.map(recipeName => {
      return (
        <div className="container">
          <div className="row">
            <div className="col-xs-12 col-sm-12 col-md-12 col-lg-12">
              <a
                href={recipeName.source_url}
                target="_blank"
                onClick={() => {
                  this.props.fetchRecipeId(recipeName.recipe_id);
                }}
              >
                <img
                  src={recipeName.image_url}
                  className="mx-auto d-block img-fluid img-thumbnail"
                  alt={recipeName.title}
                />
                <span>
                  <h3>{recipeName.title}</h3>
                </span>
              </a>
              <span}>
                <h3>{recipeName.publisher}</h3>
              </span>
            </div>
          </div>
        </div>
      );
    });
  };

  render() {
    return (
      <React.Fragment>
        {this.props.recipe.map(this.renderRecipe)}
      </React.Fragment>
    );
  }
}

Recipe_Detail.js

class RecipeDetail extends Component {
  renderRecipeDetail(recipeData) {
    return recipeData.recipe.ingredients.map(recipeIngredient => {
      return <li key={recipeIngredient}>recipeIngredient</li>;
    });
  }

  render() {
    if (this.props.recipeId === null) {
      return <div>Loading...</div>;
    }
    return <ul>{this.props.recipeId.map(this.renderRecipeDetail)}</ul>;
  }
}

function mapStateToProps({ recipeId }) {
  return { recipeId };
}

export default connect(mapStateToProps)(RecipeDetail);
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1 回答 1

1

不完全确定为什么在这里需要 Redux（除非它在其他嵌套组件之间共享），但我相当肯定你可以只使用 React 状态。

一种方法是这样配置您的路线：

    <Route path="/recipes" component={Recipes} />
    <Route path="/recipe/:id" component={ShowRecipe} />

当用户发送查询，获得一些结果，并且您将所有匹配的配方显示到Recipes组件时。然后每个recipe都有一个名称（和其他相关的可显示数据）和一个可点击的链接：

 <Link to={`/recipe/id?recipeId=${recipeId}`}>View {recipeName} Recipe</Link>

为简单起见，它可能看起来像：

<ul>
  <Link to="/recipe/id?recipeId=08861626">View Prosciutto Bruschetta Recipe</Link>
  <Link to="/recipe/id?recipeId=04326743">View Pasta Bundt Loaf Recipe</Link>
  ...etc
</ul>

当用户点击链接时，react-router 将用户发送到ShowRecipe具有唯一recipeId.

ShowRecipe 然后发出另一个 AJAX 请求以获取配方详细信息：

ShowRecipe.js

export default class ShowRecipe extends Component {
  state = { recipeDetail: '' }

  componentDidMount = () => {
     const { recipeId } = this.props.location.query; // <== only natively available in react-router v3

     fetch(`http://someAPI/recipe/id?recipeId=${recipeId}`)
      .then(response => response.json())
      .then(json => this.setState({ recipeDetail: json }));
  }

  render = () => (
    !this.state.recipeDetails
      ? <div>Loading...</div>
      : <ul>
         {this.state.recipeDetail.map(ingredient => (
           <li key={ingredient}>ingredient</li>
         )}
        </ul>
  ) 
}

另一种方法：

recipeDetails在原始获取的recipesJSON中存储并可用。然后映射recipes并<Card key={recipeId} recipeName={recipeName} recipeDetail={recipeDetail} />为每个recipe.

为简单起见，它可能看起来像：

<div>
  {this.state.recipes.map(({recipeId, recipeName, recipeDetail}), => (
    <Card key={recipeId} recipeName={recipeName} recipeDetail={recipeDetail} />
  )}
</div>

然后每张卡片都有自己的状态：

Card.js

export default class Card extends Component {
      state = { showDetails: '' }

      toggleShowDetails = () => this.setState(prevState => ({ showDetails: !this.state.showDetails }))     

      render = () => (
        <div>
          <h1>{this.props.recipeName} Recipe</h1>
          <button onClick={toggleShowDetails}> {`${!this.state.showDetails ? "Show" : "Hide"} Recipe<button>
          { this.state.showDetails &&
             <ul>
              {this.props.recipeDetail.map(ingredient => (
               <li key={ingredient}>ingredient</li>
              )}
            </ul>
          }
      ) 
    }

因此，默认情况下recipeDetail已经存在，但被隐藏了。但是，当用户单击卡片的按钮时，它将切换卡片的showDetails状态true/false以显示/隐藏配方详细信息。

于 2018-09-16T20:37:37.363 回答