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我的集合是使用以下查询实例化的：$ClassesCollection = Classes::with('Queue')->whereIn('user_course_id', UserCourse::select('id')->where('user_id', $user->id))->get();

$ClassesCollection 返回所需的结果。但是，我只想要Queue结果。

所以我这样拆分

$classes = [];

    foreach($ClassesCollection as $class){
        array_push($classes, $class->Queue);
    }

现在我有一个集合数组，每个集合都包含Queues 数组。

如何遍历这些集合以Queue在我的视图中分别显示每个 s 数组的内容？

这就是$classes成立

array:10 [▼
  0 => Collection {#968 ▼
    #items: array:12 [▼
      0 => Queue {#841 ▶}
      1 => Queue {#842 ▶}
      2 => Queue {#843 ▶}
      3 => Queue {#844 ▶}
      4 => Queue {#845 ▶}
      5 => Queue {#846 ▶}
      6 => Queue {#847 ▶}
      7 => Queue {#848 ▶}
      8 => Queue {#849 ▶}
      9 => Queue {#850 ▶}
      10 => Queue {#851 ▶}
      11 => Queue {#852 ▶}
    ]
  }
  1 => Collection {#969 ▶}
  2 => Collection {#970 ▶}
  3 => Collection {#971 ▶}
  4 => Collection {#972 ▶}
  5 => Collection {#973 ▶}
  6 => Collection {#974 ▶}
  7 => Collection {#975 ▶}
  8 => Collection {#976 ▶}
  9 => Collection {#977 ▶}
]

每个Queue都有几个属性，例如date和class_id。那么如何才能显示每个Queue的内容呢？

编辑：我认为会有一种更清洁的方法，但这就是我为遇到此问题的任何人解决问题的方法。

$count = 0;
foreach($classes as $collection => $queue){
       /*$count = count($queue) - 1;
       for($i = 0; $i <= $count; $i++){
        echo $queue[$i]->date."\n";
       }*/
       foreach($queue as $Q){
        echo $Q->date."\n";
       }
}

注释掉的代码也达到了预期的效果。

4

1 回答 1

0

使用pluck()：

$queues = $ClassesCollection->pluck('Queue')->flatten();
于 2018-09-10T16:07:08.823 回答