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所以，我让这段代码为 AABB 碰撞工作，直到我决定在 Y 轴上制作一个比在 X 轴上更大的精灵。我试图修复代码，但现在它只是将碰撞大小比实际精灵大小增加了一倍。前任。精灵 1 iVec2(50,100) 的大小，精灵 2 iVec2(30,30) 的大小。

CollisionData Collision::DoCollision(GameObject &object1, GameObject &object2) {

iVec2 center(object1.Position.x + object1.Size.x / 2, object1.Position.y + object1.Size.y / 2);

iVec2 half_extents(object2.Size.x / 2, object2.Size.y / 2);
iVec2 aabb_center(object2.Position.x + half_extents.x, object2.Position.y + half_extents.y);

iVec2 difference = center - aabb_center;
iVec2 difference2 = center - aabb_center;

iVec2 clamped = glm::clamp(difference, -half_extents, half_extents);
iVec2 clamped2 = glm::clamp(difference2, -iVec2(object1.Size.x / 2, object1.Size.y / 2), iVec2(object1.Size.x / 2, object1.Size.y / 2));

iVec2 closest = aabb_center + clamped;
iVec2 closest2 = aabb_center + clamped2;

difference = closest - center;
difference2 = closest2 - center;

if (glm::length(difference) <= object1.Size.x / 2 || glm::length(difference2) <= object1.Size.y / 2)
    return std::make_tuple(GL_TRUE, VectorDirection(difference), difference);
else return std::make_tuple(GL_FALSE, UP, glm::vec2(0, 0));

}
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1 回答 1

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我建议做一个简单的重叠检查。

如果 2 段重叠，可以通过以下方式检查：

overlap = (x1+w1) > x2 && (x2+w2) > x1

第一段x1的起点和宽度在哪里。是2n 段的起点和宽度。w1x2w2

如果要检查轴对齐的边界框是否重叠，则 ypu 必须对两个维度进行测试

bool overlap = 
    (object1.Position.x + object1.Size.x) > object2.Position.x) &&
    (object2.Position.x + object2.Size.x) > object1.Position.x) &&
    (object1.Position.y + object1.Size.y) > object2.Position.y) &&
    (object2.Position.y + object2.Size.y) > object1.Position.y);

如果你想知道重叠的数量，你必须计算盒子的中心点并将中心点的距离与盒子的共同一半大小进行比较：

CollisionData Collision::DoCollision(GameObject &object1, GameObject &object2) {

    iVec2 center1(
        object1.Position.x + object1.Size.x / 2,
        object1.Position.y + object1.Size.y / 2);
    iVec2 center2(
        object2.Position.x + object2.Size.x / 2,
         object2.Position.y + object2.Size.y / 2);

    iVec2 dist = center1 - center2;
    iVec2 size((object1.Size.x + object2.Size.x) / 2, (object1.Size.y + object2.Size.y) / 2);


    iVec2 difference = size - iVec2(abs(dist.x), abs(dist.y));

    bool overlap = difference.x > 0 && difference.y > 0;

    if ( overlap )
    {
        iVec2 min1 = object1.Position;
        iVec2 min2 = object2.Position;
        iVec2 max1 = object1.Position + object1.Size;
        iVec2 max2 = object2.Position + object2.Size;

        bool horizontal = difference.x > difference.y;
        if ( min2.x > min1.x && max1.x < max2.x || min1.x > min2.x && max2.x < max1.x )
             horizontal = false;
        else if ( min2.y > min1.y && max1.y < max2.y || min1.y > min2.y && max2.y < max1.y )
             horizontal = true;

        return std::make_tuple(
            GL_TRUE, !horizontal ? (dist.x < 0 ? LEFT: RIGHT) : (dist.y < 0 ? UP : DOWN), difference );
    }

    return std::make_tuple(GL_FALSE, UP, glm::vec2(0, 0));
}
于 2018-08-31T17:23:26.047 回答