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我正在我的 react native 项目中测试 NavigatorIOS。问题是当我按下按钮从一个组件导航到另一个组件时没有问题，但是当我尝试使用 NavigatorIOS 生成的标题栏中的按钮返回时，我收到此错误：“不支持的顶级事件”topScroll“派遣”。

我使用 react-native-cli = 2.0.1 和 react-native = 0.56.0

注意：当我按下支持组件中的“返回”按钮时，一切正常。

这是我的代码：

应用组件：

import React, { Component } from "react";
import { View, NavigatorIOS } from "react-native";

import { NavigationApp } from "./src/components/index.js";

export default class App extends Component {
  render() {
    return (
      <NavigatorIOS
        style={{ flex: 1 }}
        initialRoute={{
          title: "Navigation app",
          component: NavigationApp
        }}
      />
    );
  }
}

NavigationApp 组件：

import React, { Component } from "react";
import { Text, View, Button, NavigatorIOS } from "react-native";
import { Support } from "./index.js";

class NavigationApp extends Component {
  navigateToSupport = () => {
    this.props.navigator.push({
      title: "Support",
      component: Support
    });
  };

  render() {
    const { containerStyle } = styles;
    return (
      <View style={containerStyle}>
        <Button
          title="Go to support page"
          onPress={this.navigateToSupport}
        />
      </View>
    );
  }
}

const styles = {
  containerStyle: {
    flex: 1,
    justifyContent: "center",
    alignItems: "center"
  }
};

export { NavigationApp };

支持组件：

import React, { Component } from "react";
import { View, Text, Button } from "react-native";

class Support extends Component {
  backAction = () => {
    this.props.navigator.pop();
  };

  render() {
    return (
      <View style={{ flex: 1, justifyContent: "center", alignItems:"center" }}>
        <Text>You are in support page</Text>
        <Button title="Go back" onPress={this.backAction} />
      </View>
    );
  }
}

export { Support };
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1 回答 1

3

解决方法是将您的初始组件包装在ScrollView

<ScrollView>
  // ... Initial Component code 
</ScrollView>

这是一个未解决的问题，您可以按照这里的线索

于 2018-08-29T07:18:04.347 回答