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因此，我使用 PHP 脚本创建了一个表单，但是由于某种原因，我输入到表单中的数据没有插入到 MySQL 数据库中。我对 PHP 不太熟悉，但在网上研究了语法，但不知道哪里出了问题。我已经在下面发布了我的代码（如果它超出了解决问题的需要，请道歉）。

<!DOCTYPE>
<?php
include("includes/db.php");
?>

<html>
    <head>
        <title>Inserting Product</title>
  <script src="https://cloud.tinymce.com/stable/tinymce.min.js"></script>
  <script>
    tinymce.init({ selector:'textarea' });
  </script>
    </head>
    <!--Colour should be sky blue-->

<body bgcolor="skyblue">
    <form action="insert_product.php" method="post" enctype="multipart/form-data">
    <table align="center" width="750" border="2" bgcolor="orange">
      <tr align="center">
          <td colspan="7"><h2>Insert New Post Here</h2></td>
      </tr>
        <tr>
            <td align="right"><b>Product Title:</b></td>
            <td><input type="text" name="product_title" size="60" required/></td>
      </tr>
         <tr>
             <td align="right"><b>Product Category:</b></td>
            <td>
             <select name="product_cat" required>
                 <option>Select a Category</option>

                 <?php
                 $get_cats = "select * from categories";
                 //local variable in PHP is created using $ sign;
        // * denotes all (everything)
        $run_cats = mysqli_query($con, $get_cats);
        while ($row_cats=mysqli_fetch_array($run_cats)) {
        $cat_id = $row_cats['cat_id'];
        $cat_title = $row_cats['cat_title'];
        //local variables
        echo "<option value='$cat_id'>$cat_title</option>";
    }
                 ?>
                </select>
             </td>
      </tr>
        <tr>
            <td align="right"><b>Product Brand:</b></td>
            <td>
            <select name="product_brand" required>
                 <option>Select a Brand</option>

         <?php
                 $get_brands = "select * from brands";
    $run_brands = mysqli_query($con, $get_brands);
    while ($row_brands=mysqli_fetch_array($run_brands)) {
        $brand_id = $row_brands['brand_id'];
        $brand_title = $row_brands['brand_title'];
        echo "<option value='$brand_id'>$brand_title</option>";
    }
                 ?>
                </select>
            </td>
      </tr>
      <tr>
        <td align="right"><b>Product Image:</b></td>
        <td><input type="file" name="product_image" required/></td>
      </tr>
        <tr>
            <td align="right"><b>Product Price:</b></td>
            <td><input type="text" name="product_price" required /></td>
      </tr>
         <tr>
             <td align="right"><b>Product Description:</b></td>
             <td><textarea name="product_desc" cols="20" rows="10"></textarea></td
      </tr>
         <tr>
             <td align="right"><b>Product Keywords:</b></td>
            <td><input type="text" name="product_keywords" size="50" required/></td>
      </tr>
         <tr align="center">
            <td colspan="7"><input type="submit" name="insert_post" value="Insert Product Now" /></td>
      </tr>
   </table>
    </form>
</body>
</html>

<?php

    if(isset($_POST['insert_post'])) {
//$_POST is pre-defined/ global variable in PHP
//getting the text data from the fields

        $product_title = $_POST['product_title'];
        $product_cat = $_POST['product_cat'];
        $product_brand = $_POST['product_brand'];
        $product_price = $_POST['product_price'];
        $product_desc = $_POST['product_desc'];
        $product_keywords = $_POST['product_keywords'];
        //getting the image from the field
        $product_image = $_FILES['product_image']['name'];
        $product_image_tmp = $_FILES['product_image']['tmp_name']; //temporary/default name

move_uploaded_file($product_image_tmp,"product_images/$product_image");
            //Remove echo below once  verified that it works (only literally the word 'echo')
            echo $insert_product = "INSERT INTO products (product_cat,product_brand,product_title,product_price,product_desc,product_image,product_keywords) VALUES ('$product_cat','$product_brand','$product_title',$product_price','$product_desc','$product_image','$product_keywords')";
            //'products' is table name
            // 1st parentheses: column / fields inside table
            $insert_pro = mysqli_query($con, $insert_product);
            if($insert_pro) {
                echo "<script>alert('Product has been inserted!')</script>";
                echo "<script>window.open('insert_product.php','_self')</script>";
            }
        }

?>

我可以从 echo 语句中看到我在表单下方输入的值，但是当我检查数据库时，它们不存在。同样，JavaScript 警报也不会出现。db.php 文件中的代码建立与数据库的连接：

$con = mysqli_connect("localhost","root","","ecommerce");
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