所以这是一个完整的(希望是)示例来替换所有出现的表名。问题是,JSqlParser在别名和表名之间没有区别。如果您不想更正这些别名,则必须有一些逻辑来跳过 sql 的别名。
TableNamesFinder的使用并不能完成全部工作,因为它仅在需要查找表名时才遍历 AST,然后停止。这就是我的示例使用deparsers的原因。
此代码转换
select id, test from test where name = "test"
至
SELECT id, test FROM test_mytest WHERE name = "test"
和
select * from t2 join t1 on t1.aa = t2.bb where t1.a = "someCondition" limit 10
至
SELECT * FROM t2_mytest JOIN t1_mytest ON t1_mytest.aa = t2_mytest.bb WHERE t1_mytest.a = "someCondition" LIMIT 10
我认为这可以解决您的问题。
public class SimpleSqlParser24 {
public static void main(String args[]) throws JSQLParserException {
replaceTableName("select id, test from test where name = \"test\"");
replaceTableName("select * from t2 join t1 on t1.aa = t2.bb where t1.a = \"someCondition\" limit 10");
}
private static void replaceTableName(String sql) throws JSQLParserException {
Select select = (Select) CCJSqlParserUtil.parse(sql);
StringBuilder buffer = new StringBuilder();
ExpressionDeParser expressionDeParser = new ExpressionDeParser() {
@Override
public void visit(Column tableColumn) {
if (tableColumn.getTable() != null) {
tableColumn.getTable().setName(tableColumn.getTable().getName() + "_mytest");
}
super.visit(tableColumn);
}
};
SelectDeParser deparser = new SelectDeParser(expressionDeParser, buffer) {
@Override
public void visit(Table tableName) {
tableName.setName(tableName.getName() + "_mytest");
super.visit(tableName);
}
};
expressionDeParser.setSelectVisitor(deparser);
expressionDeParser.setBuffer(buffer);
select.getSelectBody().accept(deparser);
System.out.println(buffer.toString());
}
}