php - 使用循环从PHP中的数据库中获取数据

Question

我想在数据库的视图中显示问题及其各自的答案：

我得到了名为Feedback的数据库表，格式如下：

这是我的表名：反馈

id | employee_id | question_id |   answer            |
______________________________________________________

1  |   100       |   1         | That was awesome. 
2  |   100       |   2         | That was excellent.  
3  |   100       |   3         | That was good.  
4  |   101       |   1         | That was better.  
5  |   101       |   2         | That was interesting.  
6  |   101       |   3         | That was fine.

另一个以Questions命名的表：

id |      Question        |
_______________________________________________

1  | How was your day? 
2  | How was the task?
3  | How was the Project?

这是我的模型的代码：

function get_answers_supervisee () {
    $userid = $this->session->userdata('userid');
    $result = array ();
    $sql = "select answer from Feedback where employee_id = '$userid'";
    $query = $this->db->query ( $sql );
    foreach ( $query->result_array () as $row ) {
        array_push ( $result, $row );
    }
    return $result; 
}

以下是我的表格（客户端视图）：

<table class="table">       
     <?php foreach($form_data_supervisee as $question) {?>
     <tr>      
         <td>
         <?php echo $question['ID'].". ".$question['DESCRIPTION']?>
         </td>
    </tr>   
         <?php foreach($form_answers_supervisee as $answer) {?>                 
    <tr>   
          <td>
          <textarea rows="5" name="<?php echo $answer['ANSWER']?></textarea>
          </td> 
    </tr>   
    <?php } ?>  
    <?php }?> 
  </table>

这是我的控制器的一部分：

 $data['form_answers_supervisee'] = $this->appraisal_model->get_answers_supervisee();
     $data['form_answers_supervisor'] = $this->appraisal_model->get_answers_supervisor();

     $this->load->view('main_form',$data);

现在我得到了具有employee_id的员工的以下输出：100

1. How was your day?
   That was awesome. 
   That was excellent.
   That was good.

2. How was the task?
   That was awesome. 
   That was excellent.
   That was good.

3. How was the Project?
   That was awesome. 
   That was excellent.
   That was good.

所需的输出应该是：

1. How was your day?
   That was awesome. 

2. How was the task?
   That was excellent.

3. How was the Project?
   That was good.

我在这里需要什么更正？我究竟做错了什么？

建议高度赞赏。

score 2 · Accepted Answer

尝试以下

你的模型

function get_answers_supervisee () 
{
    $userid = $this->session->userdata('userid');

    $query = $this->db
        ->select('f.*, q.id AS question_id, q.Question')
        ->from('Feedback f')
        ->join('Questions q', 'f.question_id = q.id', 'left')
        ->where('employee_id', $userid)
        ->get();

    return $query->result();
}

控制器应该保持不变。

你的看法

<table class="table">       
     <?php 
     foreach($form_data_supervisee as $question) {
     ?>
     <tr>      
         <td>
         <p><?php echo $question->question_id.". ".$question->Question; ?></p>
         <p>Answer: <?php echo $question->answer; ?></p>
         </td>
    </tr>   
    <?php 
    }
    ?> 
</table>

作为附加说明：

您的查询对 sql 注入完全开放 - 您确实应该将内置 QueryBuilder 用于这些目的并为您自己的利益。

看看这里 https://www.codeigniter.com/userguide3/database/configuration.html#query-builder 并激活查询生成器（如果您还没有的话）。

score 1 · Accepted Answer

只需在您的视图中添加一个 if 语句即可根据问题输出答案。

 <table class="table">       
     <?php foreach($form_data_supervisee as $question) {?>
     <tr>      
         <td>
         <?php echo $question['ID'].". ".$question['DESCRIPTION']?>
         </td>
    </tr>   
         <?php foreach($form_answers_supervisee as $answer) {?>                 
    <tr>   
          <!-- check "id" in  "questions" table matches the "question_id" in "feedback" table --> 
          <?php if($question['ID'] == $answer['question_id']){ ?>
              <td>
                    <textarea rows="5" name="<?php echo $answer['ANSWER']?></textarea>
              </td>
          <?php } ?> 
    </tr>   
    <?php } ?>  
    <?php }?> 
  </table>

score 1 · Accepted Answer

希望对你有帮助：

您必须使用如下表添加join基于questions表的查询feedback：

function get_answers_supervisee () 
{
    $employee_id = $this->session->userdata('userid');
    $this->db->select('q.id , q.question,f.answer ,f.employee_id');
    $this->db->from('questions q');
    $this->db->join('feedback f','f.question_id = q.id');
    $this->db->where('f.employee_id', $employee_id);
    $result = $this->db->get()->result();
    return $result;
    //print_r($result);
}

输出看起来像：

id  question                 answer           employee_id
1   How was your day?     That was awesome.     100
2   How was the task?     That was excellent.   100
3   How was the Project?  That was good.        100

您的view访问表列如下：

<table class="table">       
     <?php foreach($form_data_supervisee as $item) {?>
     <tr>      
         <td>
         <?php echo $item->id;?>
         </td>
         <td>
         <?php echo $item->quesion;?>
         </td>
         <td>
         <?php echo $item->answer;?>
         </td>
      </tr>  

    <?php }?> 
</table>

score 0 · Accepted Answer

您好，您的查询必须基于 question_id

    <?php 

    function get_answers_supervisee ($question_id) {
        $userid = $this->session->userdata('userid');
        $result = array ();
        $sql = "select answer from Feedback where employee_id = '$userid' AND question_id = '$question_id' LIMIT 1";
        $query = $this->db->query ( $sql );
        foreach ( $query->result_array () as $row ) {
            array_push ( $result, $row );
        }
        return $result; 
    }

    ?>

php - 使用循环从PHP中的数据库中获取数据

4 回答 4

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