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我有来自不同设备的测量，比如说Device_A和Device_B。对于每台设备，我都会测量温度和湿度。有时会丢失部分或全部测量值： +---------------------+-------------+-------------+-------+ | ts | device_type | measurement | value | +---------------------+-------------+-------------+-------+ | 2018-04-30 23:59:59 | Device_A | Temperature | 10.1 | | 2018-04-30 23:59:59 | Device_A | Humidity | 66 | | 2018-04-30 23:59:59 | Device_B | Temperature | 19.1 | | 2018-05-03 23:59:59 | Device_A | Temperature | 12.1 | | 2018-05-03 23:59:59 | Device_B | Humidity | 67 | | 2018-05-03 23:59:59 | Device_B | Temperature | 16.1 | | 2018-05-04 23:59:59 | Device_A | Temperature | 17 | | 2018-05-04 23:59:59 | Device_A | Humidity | 63 | | 2018-05-04 23:59:59 | Device_B | Temperature | 12.1 | | 2018-05-04 23:59:59 | Device_B | Humidity | 73 | +---------------------+-------------+-------------+-------+

我想获得每天的平均温度和湿度，当没有数据时，我希望它为 0（或任何其他任意值） - 有趣的点在 2018-05-01 和 2018-05-02 +---------------------+-------------+-------+ | date | measurement | mean | +---------------------+-------------+-------+ | 2018-04-30 23:59:59 | Humidity | 66 | | 2018-04-30 23:59:59 | Temperature | 14.6 | | 2018-05-01 23:59:59 | Temperature | 0 | | 2018-05-01 23:59:59 | Humidity | 0 | | 2018-05-02 23:59:59 | Temperature | 0 | | 2018-05-02 23:59:59 | Humidity | 0 | | 2018-05-03 23:59:59 | Humidity | 67 | | 2018-05-03 23:59:59 | Temperature | 14.1 | | 2018-05-04 23:59:59 | Humidity | 68 | | 2018-05-04 23:59:59 | Temperature | 14.55 | +---------------------+-------------+-------+

我尝试了此处描述的间隙填充，但在测量列中遇到了 NULL 值。此外，我每天只得到一行，在 NULL 测量中根本没有任何值。理想情况下，我希望每天获得 2 行 - 一行带有温度，一行带有湿度，两者的值都设置为 0。

有没有办法像上面那样生成输出？我知道将数据从“长”格式转换为“宽”格式可以解决我的问题，但想知道是否还有其他解决方案？

我的代码：

CREATE SCHEMA tmp ;
SET search_path = tmp;

DROP TABLE IF EXISTS sample_data CASCADE;
CREATE TABLE sample_data (
  "ts" TIMESTAMP WITHOUT TIME ZONE NOT NULL,
  "device_type" character varying,
  "measurement" character varying,
  "value" DOUBLE PRECISION
);

INSERT INTO sample_data(ts, device_type, measurement, value) VALUES
('2018-04-30 23:59:59', 'Device_A', 'Temperature', 10.1),
('2018-04-30 23:59:59', 'Device_A', 'Humidity', 66.0),
('2018-04-30 23:59:59', 'Device_B', 'Temperature', 19.1),
('2018-05-03 23:59:59', 'Device_A', 'Temperature', 12.1),
('2018-05-03 23:59:59', 'Device_B', 'Humidity', 67.0),
('2018-05-03 23:59:59', 'Device_B', 'Temperature', 16.1),
('2018-05-04 23:59:59', 'Device_A', 'Temperature', 17.0),
('2018-05-04 23:59:59', 'Device_A', 'Humidity', 63.0),
('2018-05-04 23:59:59', 'Device_B', 'Temperature', 12.1),
('2018-05-04 23:59:59', 'Device_B', 'Humidity', 73.0)
;

WITH period AS (
  SELECT date
  FROM generate_series('2018-04-30 23:59:59'::timestamp, 
  '2018-05-04 23:59:59', interval '1 day') date
),
sample AS ( SELECT * FROM sample_data)

SELECT period.date,
      measurement,
      coalesce(sum(sample.value), 0) AS value
FROM period
LEFT JOIN sample ON period.date = sample.ts
GROUP BY
    period.date,
    sample.measurement
ORDER BY period.date,
        sample.measurement
;

输出： +---------------------+-------------+-------+ | date | measurement | mean | +---------------------+-------------+-------+ | 2018-04-30 23:59:59 | Humidity | 66 | | 2018-04-30 23:59:59 | Temperature | 14.6 | | 2018-05-01 23:59:59 | NULL | 0 | | 2018-05-02 23:59:59 | NULL | 0 | | 2018-05-03 23:59:59 | Humidity | 67 | | 2018-05-03 23:59:59 | Temperature | 14.1 | | 2018-05-04 23:59:59 | Humidity | 68 | | 2018-05-04 23:59:59 | Temperature | 14.55 | +---------------------+-------------+-------+

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1 回答 1

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刚刚找到答案 - 周期表还必须包含测量值：

WITH period AS (
  SELECT date, m.measurement
  FROM generate_series('2018-04-30 23:59:59'::timestamp, '2018-05-04 23:59:59', interval '1 day') date
  NATURAL JOIN
    (SELECT DISTINCT measurement FROM sample_data) m
)

SELECT period.date,
      period.measurement,
      coalesce(sum(sample_data.value), 0) AS value
FROM period
LEFT JOIN sample_data ON period.date = sample_data.ts AND period.measurement = sample_data.measurement
GROUP BY
    period.date,
    period.measurement
ORDER BY 
    period.date,
    period.measurement
;
于 2018-08-04T15:55:47.770 回答