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我想将我的日志文件转换为 zip 文件。所以为此我使用了Objective-Zip。但我得到了例外

2018-08-02 11:53:57.901192+0530 Aglive[1076:511096] *** Terminating app due to uncaught exception 'OZZipException', reason: 'Can't open 'test.zip''
*** First throw call stack:
(0x18204b164 0x181294528 0x101371724 0x101371414 0x101109318 0x101108234 0x18b71cb20 0x18b7c5760 0x18b873aa8 0x18b866e5c 0x18b5f8464 0x181ff2cdc 0x181ff0694 0x181ff0c50 0x181f10c58 0x183dbcf84 0x18b6695c4 0x100f93f80 0x181a3056c)
libc++abi.dylib: terminating with uncaught exception of type OZZipException

这是我的代码

 NSString *docDir = [NSSearchPathForDirectoriesInDomains(NSDocumentDirectory, NSUserDomainMask, YES) objectAtIndex:0];
        NSString *filePath = [docDir stringByAppendingPathComponent:@"Logfile.txt"];
        OZZipFile *zipFile= [[OZZipFile alloc] initWithFileName:@"test.zip"
                                                                      mode:OZZipFileModeCreate];
        OZZipWriteStream *stream= [zipFile writeFileInZipWithName:@"Logfile.txt"
                                                 compressionLevel:OZZipCompressionLevelBest];

        [stream writeData:filePath];
        [stream finishedWriting];

此异常发生在代码之后

OZZipFile *zipFile= [[OZZipFile alloc] initWithFileName:@"test.zip"
                                                                          mode:OZZipFileModeCreate];

我不知道为什么会发生此异常。为什么它试图打开该文件而不是创建它？

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1 回答 1

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我认为它找不到创建 zip 文件的路径。

在示例文件中，它使用以下命令创建存档：

NSString *documentsDir= [NSHomeDirectory() stringByAppendingPathComponent:@"Documents"];
NSString *filePath= [documentsDir stringByAppendingPathComponent:@"test32_64.zip"];

OZZipFile *zipFile32= [[OZZipFile alloc] initWithFileName:filePath mode:OZZipFileModeCreate legacy32BitMode:YES];

您可以看到 filePath 是 zip 路径，并以此调用 alloc init。

然后它添加文件：

OZZipWriteStream *stream= [zipFile32 writeFileInZipWithName:@"abc.txt" fileDate:[NSDate dateWithTimeIntervalSinceNow:-86400.0] compressionLevel:OZZipCompressionLevelDefault];

最后它写入并关闭流和文件：

NSMutableData *writeData= [NSMutableData dataWithLength:4096];
int result= SecRandomCopyBytes(kSecRandomDefault, [writeData length], [writeData mutableBytes]);

XCTAssertEqual(0, result);

[stream writeData:writeData];

[stream finishedWriting];

[zipFile32 close];

您最后一个问题的答案是，在所有OZZipFileMode情况下（解压缩、创建和附加）它都会在异常中打印相同的日志：

[OZZipException zipExceptionWithError:OZ_ERROR_NO_SUCH_FILE reason:@"Can't open '%@'", _fileName];
于 2018-08-02T07:08:52.297 回答