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我正在尝试从一些 VM 获取前 3 行 ip address/ifconfig - 其中一些在 Ubuntu 上运行,其中一些在 CentOS 上。

例如:

eth0: flags=4163<UP,BROADCAST,RUNNING,MULTICAST>  mtu 9001
        inet 172.31.106.100  netmask 255.255.240.0  broadcast 172.31.111.255
        inet6 fe80::10c5:1dff:fec0:803e  prefixlen 64  scopeid 0x20<link>
        ether 12:c5:1d:c0:80:3e  txqueuelen 1000  (Ethernet)
        RX packets 7483  bytes 7706844 (7.3 MiB)
        RX errors 0  dropped 0  overruns 0  frame 0
        TX packets 2998  bytes 470781 (459.7 KiB)
        TX errors 0  dropped 0 overruns 0  carrier 0  collisions 0

lo: flags=73<UP,LOOPBACK,RUNNING>  mtu 65536
        inet 127.0.0.1  netmask 255.0.0.0
        inet6 ::1  prefixlen 128  scopeid 0x10<host>
        loop  txqueuelen 1000  (Local Loopback)
        RX packets 12100  bytes 3865475 (3.6 MiB)
        RX errors 0  dropped 0  overruns 0  frame 0
        TX packets 12100  bytes 3865475 (3.6 MiB)
        TX errors 0  dropped 0 overruns 0  carrier 0  collisions 0

从这行代码中,我只需要得到以下部分:

eth0: flags=4163<UP,BROADCAST,RUNNING,MULTICAST>  mtu 9001
        inet 172.31.106.100  netmask 255.255.240.0  broadcast 172.31.111.255
        inet6 fe80::10c5:1dff:fec0:803e  prefixlen 64  scopeid 0x20<link>

lo: flags=73<UP,LOOPBACK,RUNNING>  mtu 65536
        inet 127.0.0.1  netmask 255.0.0.0
        inet6 ::1  prefixlen 128  scopeid 0x10<host>

这同样适用于 ip address 命令。有什么方法可以使用 Linux 命令来实现这一点?

非常感谢,

罗曼

4

1 回答 1

0

你可以用sed这样做,

ifconfig | sed -En '/^[^[:space:]]/,+2p; /^[[:space:]]*$/p'

简要说明,

  • 管道结果将由sed
  • /^[^[:space:]]/,+2p:搜索并打印不以空白开头的行,并打印以下两行
  • /^[[:space:]]*$/p: 搜索并打印空行
于 2018-08-01T09:20:01.613 回答