c# - 无法打开串口

Question

我在尝试打开串行端口时遇到问题，但是会发生什么：

当我告诉系统打开端口时，Try 函数没有捕获任何错误但是当我询问串行端口是否打开时，它说它不是

我正在使用带有 .NET 3.9 Compact 框架的 Visual Studio 2015 来调试 WCE2013

try
{
    string porta = "COM2";
    new frmcomunic().serialPort1.PortName     = porta;
    new frmcomunic().serialPort1.BaudRate     = 38400;
    new frmcomunic().serialPort1.DataBits     = 8;
    new frmcomunic().serialPort1.Parity       = System.IO.Ports.Parity.Even;
    new frmcomunic().serialPort1.StopBits     = System.IO.Ports.StopBits.One;
    new frmcomunic().serialPort1.Handshake    = System.IO.Ports.Handshake.XOnXOff;
    new frmcomunic().serialPort1.ReadTimeout  = 500;
    new frmcomunic().serialPort1.WriteTimeout = 500;
    new frmcomunic().serialPort1.Open();

    new frmcomunic().ProgressBar1.Value = 100;
    new frmcomunic().btcl.Enabled   = true;
    new frmcomunic().cbport.Enabled = false;
    new frmcomunic().cbrate.Enabled = false;
    new frmcomunic().btop.Enabled   = false;
    new frmcomunic().btcl.Enabled   = true;
    new frmcomunic().cbport.Enabled = true;
    new frmcomunic().cbrate.Enabled = true;
    new frmcomunic().ler            = true;
}
catch (Exception err)
{
    MessageBox.Show("Erro de Comunicação", "Aviso", MessageBoxButtons.OK, 
    MessageBoxIcon.Exclamation, MessageBoxDefaultButton.Button1);
}
if (new frmcomunic().serialPort1.IsOpen)
     MessageBox.Show("Porta aberta", "Aviso", MessageBoxButtons.OK, MessageBoxIcon.Exclamation, MessageBoxDefaultButton.Button1);
else MessageBox.Show("ERRO", "Aviso", MessageBoxButtons.OK, MessageBoxIcon.Exclamation, MessageBoxDefaultButton.Button1);

Answer 1

这对我有用

public SerialPort GetSerialPort(bool open)
            {
                SerialPort Port = new SerialPort();
                Port.PortName = PortName;
                Port.BaudRate = BaudRate;
                Port.DataBits = DataBits;
                Port.Parity = Parity;
                Port.StopBits = StopBits;
                Port.Handshake = Handshake;
                Port.ReadTimeout = ReadTimeout;
                Port.WriteTimeout = WriteTimeout;
                if (open)
                    Port.Open();
                return Port;
            }