sql - Big query replace a letter in a string by position

Question

I would to like to replace a letter in a string by position in big query. for example XXXXX, YYYYY, ZZZZZ the 5th letter in the string to 0 I've tried to use the Stuff function, but big query doesn't find the function Stuff(XXXXX, 5, 1, '0')

Answer 1

可能最简单的方法是更基本的字符串操作：

select concat(substr(x, 1, 4), '0', substr(x, 6))

Answer 2

以下是 BigQuery 标准 SQL 和旧版 SQL（两者都适用）

SELECT REGEXP_REPLACE(str, r'(.{4}).(.*)', r'\10\2')