2

我遵循 Spring Tips：Spring Cloud Gateway。但是我的网关应用程序不会从服务寄存器（Eureka）创建路由。具有 2 个参数的 DiscoveryClientRouteDefinitionLocator 构造函数。它不是从 Eureka 服务器路由的网关应用程序。我一直在尝试更改 pom.xml 中的版本，但我使用的是 RELEASE。

应用程序.java

@SpringBootApplication
public class GatewayApplication {

    @Bean
    DiscoveryClientRouteDefinitionLocator discoveryRoutes(DiscoveryClient dc, DiscoveryLocatorProperties dlp) {
        return new DiscoveryClientRouteDefinitionLocator(dc, dlp);
    }

    public static void main(String[] args) {
        SpringApplication.run(GatewayApplication.class, args);
    }
}

DiscoveryClientRouteDefinitionLocator 的构造函数现在使用 2 个参数，而不是像 Spring Tips: Spring Clou Gateway 中的 1 个。

application.property：_

spring.application.name=gateway
server.port=8081
eureka.client.register-with-eureka=true

我的pom.xml：

<?xml version="1.0" encoding="UTF-8"?>
<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
    <modelVersion>4.0.0</modelVersion>

<groupId>com.hcl.cnp</groupId>
<artifactId>gateway</artifactId>
<version>0.0.1-SNAPSHOT</version>
<packaging>jar</packaging>

<name>gateway</name>
<description>Demo project for Spring Boot</description>

<parent>
    <groupId>org.springframework.boot</groupId>
    <artifactId>spring-boot-starter-parent</artifactId>
    <version>2.0.3.RELEASE</version>
    <relativePath/> <!-- lookup parent from repository -->
</parent>

<properties>
    <project.build.sourceEncoding>UTF-8</project.build.sourceEncoding>
    <project.reporting.outputEncoding>UTF-8</project.reporting.outputEncoding>
    <java.version>1.8</java.version>
    <spring-cloud.version>Finchley.RELEASE</spring-cloud.version>
</properties>

<dependencies>
    <dependency>
        <groupId>org.springframework.boot</groupId>
        <artifactId>spring-boot-starter-actuator</artifactId>
    </dependency>
    <dependency>
        <groupId>org.springframework.boot</groupId>
        <artifactId>spring-boot-starter-data-redis</artifactId>
    </dependency>
    <!--<dependency>-->
        <!--<groupId>org.springframework.boot</groupId>-->
        <!--<artifactId>spring-boot-starter-security</artifactId>-->
    <!--</dependency>-->
    <dependency>
        <groupId>org.springframework.boot</groupId>
        <artifactId>spring-boot-starter-webflux</artifactId>
    </dependency>
    <dependency>
        <groupId>org.springframework.cloud</groupId>
        <artifactId>spring-cloud-starter-gateway</artifactId>
    </dependency>
    <dependency>
        <groupId>org.springframework.cloud</groupId>
        <artifactId>spring-cloud-starter-netflix-eureka-client</artifactId>
    </dependency>
    <dependency>
        <groupId>org.springframework.cloud</groupId>
        <artifactId>spring-cloud-starter-netflix-hystrix</artifactId>
    </dependency>

    <dependency>
        <groupId>org.springframework.boot</groupId>
        <artifactId>spring-boot-starter-test</artifactId>
        <scope>test</scope>
    </dependency>
    <dependency>
        <groupId>io.projectreactor</groupId>
        <artifactId>reactor-test</artifactId>
        <scope>test</scope>
    </dependency>
    <dependency>
        <groupId>org.springframework.security</groupId>
        <artifactId>spring-security-test</artifactId>
        <scope>test</scope>
    </dependency>
</dependencies>

<dependencyManagement>
    <dependencies>
        <dependency>
            <groupId>org.springframework.cloud</groupId>
            <artifactId>spring-cloud-dependencies</artifactId>
            <version>${spring-cloud.version}</version>
            <type>pom</type>
            <scope>import</scope>
        </dependency>
    </dependencies>
</dependencyManagement>

<build>
    <plugins>
        <plugin>
            <groupId>org.springframework.boot</groupId>
            <artifactId>spring-boot-maven-plugin</artifactId>
        </plugin>
    </plugins>
</build>


</project>
4

2 回答 2

2

让它工作。你不需要在下面添加bean，删除它

@Bean
DiscoveryClientRouteDefinitionLocator discoveryRoutes(DiscoveryClient dc, DiscoveryLocatorProperties dlp) {
    return new DiscoveryClientRouteDefinitionLocator(dc, dlp);
}

在您的 application.properties 中，添加这两行以启用发现客户端

spring.cloud.gateway.discovery.locator.enabled=true
spring.cloud.gateway.discovery.locator.lower-case-service-id=true

它应该工作！

于 2019-01-06T15:26:47.133 回答
1

构造函数DiscoveryClientRouteDefinitionLocator (DiscoveryClient, DiscoveryLocatorProperties) 已弃用

我建议你使用：

ReactiveDiscoveryClient而不是DiscoveryClient

@Bean
DiscoveryClientRouteDefinitionLocator discoveryRoutes(ReactiveDiscoveryClient rdc,
        DiscoveryLocatorProperties dlp) {
    return new DiscoveryClientRouteDefinitionLocator(rdc, dlp);
}

其他的事情，你应该把你的application.propery重命名为application.properities

于 2020-05-29T19:24:29.270 回答