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我正在使用 Swift 编程语言开发 iOS App
我有以下 JSON 格式的数据：

 [{
"agid": 10,
"alarmStatus": 8,
"alarmTransactions": [{
    "alarmTransactionID": 1,
    "systemID": 1,
    "agid": 10,
    "assignedTo": "3969ca82-905b-4df6-a30c-30c64c76f8b0",
    "userName": "Shankar",
    "email": "abc@gmail.com",
    "alarmStatus": 3,
    "alarmDate": "1532359240.1231313213"
}, {
    "alarmTransactionID": 2,
    "systemID": 1,
    "agid": 10,
    "assignedTo": "3969ca82-905b-4df6-a30c-30c64c76f8b0",
    "userName": "Satya",
    "email": "xyz@gmail.com",
    "alarmStatus": 4,
    "alarmDate": "1532359240.234234325"
}]
}]

上面的代码具有某些键值对，我只对在下面提到的结构对象中获取“alarmTransactions”数组感兴趣。

struct AlarmHistory: Codable {
    let userName: String
    let alarmStatus: Int
    let alarmDate: Double
}

下面的代码肯定会失败，因为我的 json 有许多我不感兴趣的其他关键值细节。

do {
     let alarmsHistory = try JSONDecoder().decode([AlarmHistory].self, from: data)
   } catch {
     print("Exception: \(error.localizedDescription)")
   }

有人可以建议我如何将我的“alarmTransactions”解析为 [AlarmHistory] ​​对象吗？

4

1 回答 1

1

你可以试试这个

struct AlarmHistory : Codable {
    let agid, alarmStatus: Int
    let alarmTransactions: [AlarmTransaction]
}

struct AlarmTransaction: Codable {
    let alarmTransactionID, systemID, agid: Int
    let assignedTo, userName, email: String
    let alarmStatus: Int
    let alarmDate: String
}

//

do {

    let arr = try JSONDecoder().decode([AlarmHistory].self, from: data) 

    print(arr)

}
catch {

    print(error)
}
于 2018-07-23T13:37:40.867 回答