45

我正在寻找一种方法来包含/排除文件模式并从os.walk()调用中排除目录。

这是我现在正在做的事情：

import fnmatch
import os

includes = ['*.doc', '*.odt']
excludes = ['/home/paulo-freitas/Documents']

def _filter(paths):
    for path in paths:
        if os.path.isdir(path) and not path in excludes:
            yield path

        for pattern in (includes + excludes):
            if not os.path.isdir(path) and fnmatch.fnmatch(path, pattern):
                yield path

for root, dirs, files in os.walk('/home/paulo-freitas'):
    dirs[:] = _filter(map(lambda d: os.path.join(root, d), dirs))
    files[:] = _filter(map(lambda f: os.path.join(root, f), files))

    for filename in files:
        filename = os.path.join(root, filename)

        print(filename)

有一个更好的方法吗？如何？

4

8 回答 8

57

此解决方案用于fnmatch.translate将 glob 模式转换为正则表达式（假设包含仅用于文件）：

import fnmatch
import os
import os.path
import re

includes = ['*.doc', '*.odt'] # for files only
excludes = ['/home/paulo-freitas/Documents'] # for dirs and files

# transform glob patterns to regular expressions
includes = r'|'.join([fnmatch.translate(x) for x in includes])
excludes = r'|'.join([fnmatch.translate(x) for x in excludes]) or r'$.'

for root, dirs, files in os.walk('/home/paulo-freitas'):

    # exclude dirs
    dirs[:] = [os.path.join(root, d) for d in dirs]
    dirs[:] = [d for d in dirs if not re.match(excludes, d)]

    # exclude/include files
    files = [os.path.join(root, f) for f in files]
    files = [f for f in files if not re.match(excludes, f)]
    files = [f for f in files if re.match(includes, f)]

    for fname in files:
        print fname
于 2011-02-28T12:15:22.897 回答
24

来自docs.python.org：

os.walk(top[, topdown=True[, onerror=None[, followlinks=False]]])

当 topdown 为 True 时，调用者可以就地修改 dirnames 列表……这可用于修剪搜索……</p> 

for root, dirs, files in os.walk('/home/paulo-freitas', topdown=True):
    # excludes can be done with fnmatch.filter and complementary set,
    # but it's more annoying to read.
    dirs[:] = [d for d in dirs if d not in excludes] 
    for pat in includes:
        for f in fnmatch.filter(files, pat):
            print os.path.join(root, f)

我应该指出，上面的代码假设excludes是一个模式，而不是一个完整的路径。您需要调整列表理解以过滤是否os.path.join(root, d) not in excludes匹配 OP 案例。

于 2011-02-28T12:02:18.540 回答
10

为什么选择 fnmatch？

import os
excludes=....
for ROOT,DIR,FILES in os.walk("/path"):
    for file in FILES:
       if file.endswith(('doc','odt')):
          print file
    for directory in DIR:
       if not directory in excludes :
          print directory

没有经过详尽的测试

于 2011-02-28T11:42:38.967 回答
1

ditools非常适合您的用例：

from dirtools import Dir

print(Dir('.', exclude_file='.gitignore').files())
于 2014-07-18T21:42:20.667 回答
0

这是一种方法

import fnmatch
import os

excludes = ['/home/paulo-freitas/Documents']
matches = []
for path, dirs, files in os.walk(os.getcwd()):
    for eachpath in excludes:
        if eachpath in path:
            continue
    else:
        for result in [os.path.abspath(os.path.join(path, filename)) for
                filename in files if fnmatch.fnmatch(filename,'*.doc') or fnmatch.fnmatch(filename,'*.odt')]:
            matches.append(result)
print matches
于 2011-02-28T11:51:30.183 回答
0 
import os
includes = ['*.doc', '*.odt']
excludes = ['/home/paulo-freitas/Documents']
def file_search(path, exe):
for x,y,z in os.walk(path):
    for a in z:
        if a[-4:] == exe:
            print os.path.join(x,a)
        for x in includes:
            file_search(excludes[0],x)
于 2012-12-26T05:33:26.963 回答
0

这是排除目录和文件的示例os.walk()：

ignoreDirPatterns=[".git"]
ignoreFilePatterns=[".php"]
def copyTree(src, dest, onerror=None):
    src = os.path.abspath(src)
    src_prefix = len(src) + len(os.path.sep)
    for root, dirs, files in os.walk(src, onerror=onerror):
        for pattern in ignoreDirPatterns:
            if pattern in root:
                break
        else:
            #If the above break didn't work, this part will be executed
            for file in files:
                for pattern in ignoreFilePatterns:
                    if pattern in file:
                        break
                else:
                    #If the above break didn't work, this part will be executed
                    dirpath = os.path.join(dest, root[src_prefix:])
                    try:
                        os.makedirs(dirpath,exist_ok=True)
                    except OSError as e:
                        if onerror is not None:
                            onerror(e)
                    filepath=os.path.join(root,file)
                    shutil.copy(filepath,dirpath)
                continue;#If the above else didn't executed, this will be reached

        continue;#If the above else didn't executed, this will be reached

python >=3.2由于exist_ok在makedirs

于 2015-05-11T18:57:56.377 回答
0

上述方法对我不起作用。

所以，这就是我对另一个问题的原始答案的扩展。

对我有用的是：

if (not (str(root) + '/').startswith(tuple(exclude_foldr)))

它编译了一个路径并排除了我列出的文件夹的元组。

这给了我想要的确切结果。

我的目标是让我的 mac 井井有条。

我可以搜索任何folder，具体的，如果他们是文件path，我会先发制人。locate & movefile.typesignore subfoldersprompt the userwant to move

注意：Prompt每次运行只有一次，而不是每个文件

默认情况下，提示默认为NO当您按 Enter 而不是 [y/N] 时，并且只会列出Potential要移动的文件。

这只是我的 GitHub 的一个片段，请访问整个脚本。

提示：阅读下面的脚本，因为我每行添加了关于我所做的事情的信息。

#!/usr/bin/env python3
# =============================================================================
# Created On  : MAC OSX High Sierra 10.13.6 (17G65)
# Created On  : Python 3.7.0
# Created By  : Jeromie Kirchoff
# =============================================================================
"""THE MODULE HAS BEEN BUILD FOR KEEPING YOUR FILES ORGANIZED."""
# =============================================================================
from os import walk
from os import path
from shutil import move
import getpass
import click

mac_username = getpass.getuser()
includes_file_extensn = ([".jpg", ".gif", ".png", ".jpeg", ])
search_dir = path.dirname('/Users/' + mac_username + '/Documents/')
target_foldr = path.dirname('/Users/' + mac_username + '/Pictures/Archive/')
exclude_foldr = set([target_foldr,
                    path.dirname('/Users/' + mac_username +
                                 '/Documents/GitHub/'),
                     path.dirname('/Users/' + mac_username +
                                  '/Documents/Random/'),
                     path.dirname('/Users/' + mac_username +
                                  '/Documents/Stupid_Folder/'),
                     ])

if click.confirm("Would you like to move files?",
                 default=False):
    question_moving = True
else:
    question_moving = False


def organize_files():
    """THE MODULE HAS BEEN BUILD FOR KEEPING YOUR FILES ORGANIZED."""
    # topdown=True required for filtering.
    # "Root" had all info i needed to filter folders not dir...
    for root, dir, files in walk(search_dir, topdown=True):
        for file in files:
            # creating a directory to str and excluding folders that start with
            if (not (str(root) + '/').startswith(tuple(exclude_foldr))):
                # showcase only the file types looking for
                if (file.endswith(tuple(includes_file_extensn))):
                    # using path.normpath as i found an issue with double //
                    # in file paths.
                    filetomove = path.normpath(str(root) + '/' +
                                               str(file))
                    # forward slash required for both to split
                    movingfileto = path.normpath(str(target_foldr) + '/' +
                                                 str(file))
                    # Answering "NO" this only prints the files "TO BE Moved"
                    print('Files To Move: ' + str(filetomove))
                    # This is using the prompt you answered at the beginning
                    if question_moving is True:
                        print('Moving File: ' + str(filetomove) +
                              "\n To:" + str(movingfileto))
                        # This is the command that moves the file
                        move(filetomove, movingfileto)
                        pass

            # The rest is ignoring explicitly and continuing
                    else:
                        pass
                    pass
                else:
                    pass
            else:
                pass


if __name__ == '__main__':
    organize_files()

从终端运行我的脚本的示例：

$ python3 organize_files.py
Exclude list: {'/Users/jkirchoff/Pictures/Archive', '/Users/jkirchoff/Documents/Stupid_Folder', '/Users/jkirchoff/Documents/Random', '/Users/jkirchoff/Documents/GitHub'}
Files found will be moved to this folder:/Users/jkirchoff/Pictures/Archive
Would you like to move files?
No? This will just list the files.
Yes? This will Move your files to the target folder.
[y/N]:

列出文件的示例：

Files To Move: /Users/jkirchoff/Documents/Archive/JayWork/1.custom-award-768x512.jpg
Files To Move: /Users/jkirchoff/Documents/Archive/JayWork/10351458_318162838331056_9023492155204267542_n.jpg
...etc

移动文件示例：

Moving File: /Users/jkirchoff/Documents/Archive/JayWork/1.custom-award-768x512.jpg
To: /Users/jkirchoff/Pictures/Archive/1.custom-award-768x512.jpg
Moving File: /Users/jkirchoff/Documents/Archive/JayWork/10351458_318162838331056_9023492155204267542_n.jpg
To: /Users/jkirchoff/Pictures/Archive/10351458_318162838331056_9023492155204267542_n.jpg
...
于 2018-08-16T07:20:59.477 回答