0

如何将坐标保存在 localstorage 中，这样它就不会每次都要求用户允许 GPS 或 Location 和一个按钮来清除 localstorage 值，以便它可以再次询问坐标？

仅供参考：我正在使用Praytimes JS显示穆斯林祈祷时间，但对于每个位置，我必须手动添加该位置的纬度和经度。

下面是我的代码：

<script type="text/javascript" src="https://maps.google.com/maps/api/js?sensor=false"></script>
<script type="text/javascript"> 
  var x = document.getElementById("currentlocation");

  var geocoder;

  if (navigator.geolocation) {
    navigator.geolocation.getCurrentPosition(successFunction, errorFunction);
} 
//Get the latitude and the longitude;
function successFunction(position) {
    var lat = position.coords.latitude;
    var lng = position.coords.longitude;
    codeLatLng(lat, lng)
}

function errorFunction(){
    $('#currentlocation').html("Geocoder failed");
}

  function initialize() {
    geocoder = new google.maps.Geocoder();



  }

  function codeLatLng(lat, lng) {

    var latlng = new google.maps.LatLng(lat, lng);
    geocoder.geocode({'latLng': latlng}, function(results, status) {
      if (status == google.maps.GeocoderStatus.OK) {
      console.log(results)
        if (results[1]) {
         //formatted address
         $('#currentlocation').html(results[0].formatted_address);
        //find country name
             for (var i=0; i<results[0].address_components.length; i++) {
            for (var b=0;b<results[0].address_components[i].types.length;b++) {

            //there are different types that might hold a city admin_area_lvl_1 usually does in come cases looking for sublocality type will be more appropriate
                if (results[0].address_components[i].types[b] == "administrative_area_level_2") {
                    //this is the object you are looking for
                    city= results[0].address_components[i];
                    break;
                }
            }
        }
        //city data
        $('#currentlocation').html(city.short_name + " " + city.long_name)


        } else {
          $('#currentlocation').html("No results found");
        }
      } else {
        $('#currentlocation').html("Geocoder failed due to: " + status);
      }
    });
  }
</script>

<p id="currentlocation"></p>

<script type="text/javascript" src="http://praytimes.org/code/v2/js/PrayTimes.js"></script>    

<script type="text/javascript">
    function loadTable(position) {
        prayTimes.setMethod('MWL'); 
        var date = new Date(); // today
        var times = prayTimes.getTimes(date, [position.coords.latitude, position.coords.longitude]);
        var list = ['Fajr', 'Sunrise', 'Dhuhr', 'Asr', 'Maghrib', 'Isha', 'Midnight'];

        var html = '<table id="timetable">';
        html += '<tr><th colspan="2">'+ date.toLocaleDateString()+ '</th></tr>';
        for(var i in list)  {
            html += '<tr><td>'+ list[i]+ '</td>';
            html += '<td>'+ times[list[i].toLowerCase()]+ '</td></tr>';
        }
        html += '</table>';
        document.getElementById('table').innerHTML = html;
    }

    if (navigator.geolocation) {
        navigator.geolocation.getCurrentPosition(loadTable);
    }
</script>
4

2 回答 2

1

用坐标信息定义一个对象：

var coordinatesObject = 
{
  lat: position.coords.latitude,
  lng: position.coords.longitude
}

将其保存在本地存储中：

localStorage.setItem('coordinates', 
JSON.stringify(coordinatesObject));

得到它：

let objFromLocalStorage = 
localStorage.getItem('coordinates');
于 2018-07-08T08:03:09.410 回答
0 
var CACHED_POSITION = "CACHED_POSITION";

var x = document.getElementById("currentlocation");

var geocoder;

(function () {
    if (navigator.geolocation) {
        try {
            var position = JSON.parse(window.localStorage[CACHED_POSITION]);
            if (position) {
                successFunction(position);
                return;
            }
        } catch (e) {

        }
        navigator.geolocation.getCurrentPosition(successFunction, errorFunction);
    }
})();

//Get the latitude and the longitude;
function successFunction(position) {
    window.localStorage[CACHED_POSITION] = JSON.stringify(position);

    var lat = position.coords.latitude;
    var lng = position.coords.longitude;//Save to cache
    codeLatLng(lat, lng);
}
于 2018-07-08T08:27:23.397 回答