-1

当我在列表和元组之间更改输出类型时,一个显示输出,而另一个仅显示结果的位置。为什么会这样?

>>> symbol = '123456789'
>>> (s for s in symbol)
<generator object <genexpr> at 0x7fc0e9e2fbf8>
>>> [s for s in symbol]
['1', '2', '3', '4', '5', '6', '7', '8', '9']
4

1 回答 1

-1

(s for s in symbol)是生成器理解。如同:

symbol = '123456789'
def func():
    for s in symbol:
        yield s

g = func()
print(g)
<generator object func at 0x7ffff7e59410>

print(tuple(g)) 
('1', '2', '3', '4', '5', '6', '7', '8', '9')

如果您向list()或供应发电机tuple(),发电机将运行。

于 2018-07-07T14:50:36.117 回答