我已经审查了许多关于这个主题的堆栈溢出线程,尤其是这个 jQuery serializeArray 没有选择动态创建的表单元素,但没有一个能够解决问题
我正在通过 firebase 数据库搜索匹配项。如果匹配,则显示表单 A,但如果没有匹配,则显示表单 B。
return CatalogueDB.ref('/FSC/Misc/' + splitinput[index]).once('value').then(function(snapshot) {
console.log(snapshot.val())
var key = snapshot.val().NSN
var Name = snapshot.val().Nomenclature
var resultcard = `
<form id="myform">
<tr class="tr-shadow">
<td style="width: 90px;">
<div>${key}
</div>
<div>
<br>
<button type="button" class="btn btn-secondary mb-1 btn-sm" data-toggle="modal" data-target="#mediumModal">
Add Photos
</button>
</div>
</td><td>
<span class="block ">
${Name}
</span>
</td>
<td class="desc">
<input class="au-input au-input--sm" type="text" name="search" placeholder="i.e. 20 EA" style="width: 100px;" />
</td>
<td>
<span class="status--process">
<input class="au-input au-input--sm" type="text" name="search" placeholder="Search for datas & reports..." style="width: 90px;" />
</span>
</td>
<td>
<button type="button" class="btn btn-primary btn-md" onclick="postitem(this);">Submit</button>
</td>
</tr>
</form>
<tr class="spacer"></tr>
`
container.innerHTML += resultcard;
})
.catch(function(error) {
container.innerHTML += "";
var errorcard = `
<form id="myform">
<tr class="tr-shadow">
<td style="width: 90px;">
<div>${splitinput[index]}
</div>
</td>
<td>
<span class="status--process">
<input class="au-input au-input--sm" type="text" name="search" placeholder="Search for datas & reports..." style="width: 90px;" />
</span>
</td>
<td>
<span class="status--process">
<input class="au-input au-input--sm" type="text" name="search" placeholder="Search for datas & reports..." style="width: 90px;" />
</span>
</td>
<td class="desc">
<input class="au-input au-input--sm" type="text" name="search" placeholder="Search for datas & reports..." style="width: 90px;" />
</td>
<td>
<button type="button" class="btn btn-primary btn-md" onclick="postitem(this)">Submit</button>
</td>
</tr>
</form>
`
container.innerHTML += errorcard;
})
});
我想在单击提交按钮时从表单中获取输入值,因此这个函数
function postitem() {
var data = $('#myform').serializeArray();
console.log(data)
}
不检索和显示输入值。如何捕获提交按钮的点击输入值