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我正在尝试在一个应用程序中同时使用django-viewflowdjango-permission的想法,其中会有一些复杂的权限规则。我理解 django-permission 工作方式的方式是向要应用权限规则的视图添加装饰器。

通过扩展基本视图流视图并将 urls.py 指向扩展视图,我已设法在流程视图上进行此操作。当我尝试对任务遵循相同的想法时,我遇到了下面列出的错误

类型对象“CBVTask”没有属性“flow_class”

模型.py

class CBVArticle(models.Model):
    created_by = models.ForeignKey(User)
    title = models.CharField(max_length=100)
    content = models.TextField()

class CBVArticleProcess(Process):
    article = models.ForeignKey(CBVArticle, blank=True, null=True)

class CBVTask(Task):

    class Meta:
        proxy = True

流.py

class CBVArticleFlow(Flow):
    process_class = models.CBVArticleProcess
    task_class = models.CBVTask

    start = (
        flow.Start(views.ArticleCreate).Next(this.end)
    )

    end =flow.End()

网址.py

myflow_urls = FlowViewSet(CBVArticleFlow).urls  

urlpatterns = [
    url(r'^process/(?P<process_pk>\d+)/$', views.TestDetailProcessView.as_view(), kwargs = dict(flow_class=CBVArticleFlow), name='detail'),
    url(r'^process/(?P<process_pk>\d+)/start/(?P<task_pk>\d+)/detail/$', views.DetailTaskView.as_view(), kwargs = dict(flow_class=CBVArticleFlow, flow_task=CBVTask), name='start__detail'),
]

视图.py

from viewflow.flow.views import DetailProcessView as BaseDetailProcessView, DetailTaskView as BaseDetailTaskView

@permission_required('test_app_cbv.view_cbvarticleprocess')
class TestDetailProcessView(BaseDetailProcessView):
    template_name = 'test_app_cbv/detail.html'

    def get_queryset(self):
        pk = self.kwargs['process_pk']

        return models.CBVArticleProcess.objects.filter(process_ptr_id = pk)

class DetailTaskView(BaseDetailTaskView):
    template_name = 'test_app_cbv/task_detail.html'

提前感谢您的任何指点!

4

1 回答 1

1

原来是一个新手错误 - urls.py 文件应该如下所示:

网址.py

myflow_urls = FlowViewSet(CBVArticleFlow).urls  

urlpatterns = [
    url(r'^process/(?P<process_pk>\d+)/$', views.TestDetailProcessView.as_view(), kwargs = dict(flow_class=CBVArticleFlow), name='detail'),
    url(r'^process/(?P<process_pk>\d+)/start/(?P<task_pk>\d+)/detail/$', views.DetailTaskView.as_view(), kwargs = dict(flow_class=CBVArticleFlow, flow_task=CBVArticleFlow.start), name='start__detail'),
]
于 2018-07-12T11:54:46.300 回答