1

这个答案中,提供了一种检查 Lua 函数签名的方法。答案指出:

该算法适用于 Lua 5.2。旧版本会相似但不一样:

Lua 5.1 中的等价物是什么?

4

1 回答 1

2
function funcsign(f)
   assert(type(f) == 'function', "bad argument #1 to 'funcsign' (function expected)")
   local p = {}
   pcall(
      function()
         local oldhook
         local delay = 2
         local function hook(event, line)
            delay = delay - 1
            if delay == 0 then
               for i = 1, math.huge do
                  local k, v = debug.getlocal(2, i)
                  if type(v) == "table" then
                     table.insert(p, "...")
                     break
                  elseif (k or '('):sub(1, 1) == '(' then
                     break
                  else
                     table.insert(p, k)
                  end
               end
               if debug.getlocal(2, -1) then
                  table.insert(p, "...")
               end
               debug.sethook(oldhook)
               error('aborting the call')
            end
         end
         oldhook = debug.sethook(hook, "c")
         local arg = {}
         for j = 1, 64 do arg[#arg + 1] = true end
         f((table.unpack or unpack)(arg))
      end)
   return "function("..table.concat(p, ",")..")"
end

用法:

local function somefunc(a, b, c, ...)
   return 
end

print(funcsign(somefunc))
于 2018-06-29T12:50:24.403 回答