1

我已经使用 asp.net C# 成功集成了 Human_Resources 和 Financial_Management。所以我把我遇到的所有问题和我在网上找到的有用资源放在一起：

WorkDay 文档位于： https ://community.workday.com/sites/default/files/file-hosting/productionapi/index.html

要开始使用，请在此处阅读http://hr.dovetailsoftware.com/gcox/2014/06/13/getting-started-workday-web-services-using-c/确保遵循本文中的一些清理提示。

如果您在向 WD 提交数据时遇到同样的错误

错误

There was an error in serializing one of the headers in message Get_ProjectsInput: ‘Unable to generate a temporary class (result=1).
error CS0030: Cannot convert type ‘ConsoleApplication1.WkDay.Rm.Asset_Book_Rule_Request_CriteriaType’ to ‘ConsoleApplication1.WkDay.Rm.Asset_Book_Rule_Request_ReferencesType’
error CS0030: Cannot convert type ‘ConsoleApplication1.WkDay.Rm.Asset_Shares_Request_CriteriaType’ to ‘ConsoleApplication1.WkDay.Rm.Asset_Shares_Request_ReferenceType’
error CS0029: Cannot implicitly convert type ‘ConsoleApplication1.WkDay.Rm.Asset_Book_Rule_Request_ReferencesType’ to ‘ConsoleApplication1.WkDay.Rm.Asset_Book_Rule_Request_CriteriaType’
error CS0029: Cannot implicitly convert type ‘ConsoleApplication1.WkDay.Rm.Asset_Shares_Request_ReferenceType’ to ‘ConsoleApplication1.WkDay.Rm.Asset_Shares_Request_CriteriaType’
‘. Please see InnerException for more details.
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2 回答 2

2

注释掉

[System.Xml.Serialization.XmlElementAttribute("Request_References", typeof(), Order=0)]

/// <remarks/>
    [System.Xml.Serialization.XmlElementAttribute("Request_Criteria", typeof(Asset_Book_Rule_Request_CriteriaType), Order=Asset_Book_Rule_Request_ReferencesType0)]
    //anr [System.Xml.Serialization.XmlElementAttribute("Request_References", typeof(), Order=0)]
    [System.Xml.Serialization.XmlChoiceIdentifierAttribute("ItemElementName")]
    public Asset_Book_Rule_Request_CriteriaType Item
    {
        get
        {
            return this.itemField;
        }
        set
        {
            this.itemField = value;
        }
    }

于 2018-07-01T01:53:28.160 回答
1

使用 Workday WS v32.1，这仍然是一个问题，但解决方案适用。

[System.Xml.Serialization.XmlElementAttribute("Request_Criteria", typeof(Asset_Book_Rule_Request_CriteriaType), Order = 0)]
//[System.Xml.Serialization.XmlElementAttribute("Request_References", typeof(Asset_Book_Rule_Request_ReferencesType), Order = 0)]
[System.Xml.Serialization.XmlChoiceIdentifierAttribute("ItemElementName")]
        public Asset_Book_Rule_Request_CriteriaType Item
        {
            get { return this.itemField; }
            set { this.itemField = value; }
        }
于 2019-07-08T22:59:12.243 回答