0

我的登录页面只是说

解析错误：文件意外结束

在此处输入图像描述

你能帮我么？

我正在使用 XAMPP（我认为这不是问题，但我正在写尽可能多的细节以使其更容易回答）。

    <?php
$Password = $_POST['Password'];
$Password = hash('sha256', '$Password');

$host = "localhost";
$user = "root";
// $password = "";
$dbName = "db1";
$dbTable = "users";

$link = mysqli_connect ($host, $user, $password);
$query = "SELECT * from ".$dbTable." WHERE Username = '$Username' AND Password = '$Password'";
$result = mysql_db_query($dbName, $query, $link);

while ($row = mysql_fetch_array($result)) {
    print("$row[user]<br>");
    print("$row[domain]<br>");
}
mysql_close ($link);
if ($row[user] == $clientUser || $row[domain] == $clientDomain) {
    print("<h1>NOPE!</h1>\
");
?>



<!DOCTYPE html>
<html>
<head>
    <title>Log In</title>
</head>
<body>
    <form action="index.php" method="POST">
        <label>Username:</label>
        <br>
        <input type="text" name="Username" placeholder="Username">
        <br>
        <br>
        <label>Password:</label>
        <br>
        <input type="text" name="Password" placeholder="Password">
        <button type="submit" name="login">Log In</button>
    </form>
</body>
</html>
4

2 回答 2

0

您可能没有为第 22 行中的 if 条件加上大括号

看到这个答案

<?php
$Password = $_POST['Password'];
$Password = hash('sha256', '$Password');

$host = "localhost";
$user = "root";
// $password = "";
$dbName = "db1";
$dbTable = "users";

$link = mysqli_connect ($host, $user, $password);
$query = "SELECT * from ".$dbTable." WHERE Username = '$Username' AND Password = '$Password'";
$result = mysql_db_query($dbName, $query, $link);

while ($row = mysql_fetch_array($result)) {
    print("$row[user]<br>");
    print("$row[domain]<br>");
}
mysql_close ($link);
if ($row[user] == $clientUser || $row[domain] == $clientDomain) {
    print("<h1>NOPE!</h1>\
    ");
}
?>



<!DOCTYPE html>
<html>
<head>
    <title>Log In</title>
</head>
<body>
    <form action="index.php" method="POST">
        <label>Username:</label>
        <br>
        <input type="text" name="Username" placeholder="Username">
        <br>
        <br>
        <label>Password:</label>
        <br>
        <input type="text" name="Password" placeholder="Password">
        <button type="submit" name="login">Log In</button>
    </form>
</body>
</html>
于 2018-06-27T21:12:58.010 回答
0 
<?php
$Password = $_POST['Password'];
$Password = hash('sha256', '$Password');

$host = "localhost";
$user = "root";
// $password = "";
$dbName = "db1";
$dbTable = "users";

$link = mysqli_connect ($host, $user, $password);
$query = "SELECT * from ".$dbTable." WHERE Username = '$Username' AND Password = '$Password'";
$result = mysql_db_query($dbName, $query, $link);

while ($row = mysql_fetch_array($result)) {
    print("$row[user]<br>");
    print("$row[domain]<br>");
}
mysql_close ($link);
if ($row[user] == $clientUser || $row[domain] == $clientDomain) { 
print( "<h1>NOPE!</h1>");
}
?>



<!DOCTYPE html>
<html>
<head>
    <title>Log In</title>
</head>
<body>
    <form action="index.php" method="POST">
        <label>Username:</label>
        <br>
        <input type="text" name="Username" placeholder="Username">
        <br>
        <br>
        <label>Password:</label>
        <br>
        <input type="text" name="Password" placeholder="Password">
        <button type="submit" name="login">Log In</button>
    </form>
</body>
</html>
于 2018-06-27T21:13:53.177 回答