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我经常在库（汽车）中使用“重新编码”功能来重新编码变量中的级别。直到今天我的代码都运行良好，但现在它给我带来了错误。df 等没有任何变化，不确定发生了什么。
可能有人可以启发我！

我的数据框（示例）：

test<-structure(list(Avg.Salary = c("65000", "395", "82000", "128357", 
"95785", "95785"), Education = c("Doctorate", "Professional Degree", 
"Bachelor's", "Professional Degree", "Master's", "Master's"), 
Count = c("D", "D", "D", "D", "D", "364584"), Year = c(2017, 
2017, 2017, 2017, 2017, 2017)), row.names = c("540061", "540071", 
"540081", "540091", "540102", "540112"), class = "data.frame")

我的实际数据集中的级别：-

    Associate Degree           Associates           Bachelor's 
             205                   35                42446 
               D            Doctorate          High School 
           42902                 9846                  191 
        Master's    Missing Education           No Diploma 
           57644                  218                   79 
    Professional  Professional Degree         Some College 
             431                 6791                   60 
 Some College Credits 
             370

我的代码（直到今天都运行良好！）：-

# Recode the education levels
test$Education<-recode(test$Education,
                 "c('Associate Degree','Associates','D','High School',
                    'No Diploma','Missing Education',
                    'Professional','Professional Degree','Some College',
                    'Some College Credits')='Others'")

错误：-Error: Argument 2 must be named, not unnamed

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1 回答 1

8

它对我来说是一个干净的会话。我猜 与car::recode()冲突dplyr::recode()。限定功能是否有效？替换recode为car::recode。

test$Education <- car::recode(test$Education,
                 "c('Associate Degree','Associates','D','High School',
                    'No Diploma','Missing Education',
                    'Professional','Professional Degree','Some College',
                    'Some College Credits')='Others'")

当我dplyr::recode()明确调用时，我收到“错误：参数 2 必须命名，而不是未命名”的错误。

test$Education <- dplyr::recode(...)
于 2018-06-27T16:26:23.050 回答