1

我找不到描述 return 关键字的相关文档。这是在哪里记录的？

我正在运行以下查询

POST /myindex/mytype/FwOaGmQBdhLB1nuQhK1Q/_update
{
  "script": {
    "source": """
      if (ctx._source.owner._id.equals(params.signedInUserId)){
        for (int i = 0; i < ctx._source.managers.length; i++) {
          if (ctx._source.managers[i].email.equals(params.managerEmail)) {
            ctx._source.managers.remove(i);
            return;
          }
        }
      }
      ctx.op = 'noop';
    """,
    "lang": "painless",
    "params": {
      "signedInUserId": "auth0|5a78c1ccebf64a46ecdd0d9c",
      "managerEmail": "d@d.com"
    }
  },
  "_source": true
}

但我得到了错误

"type": "illegal_argument_exception",
"reason": "failed to execute script",
"caused_by": {
  "type": "script_exception",
  "reason": "compile error",
  "script_stack": [
    "... ve(i);\n            return;\n          }\n        }\n  ...",
    "                             ^---- HERE"
  ],
  "script": <the script here>,
  "lang": "painless",
  "caused_by": {
    "type": "illegal_argument_exception",
    "reason": "invalid sequence of tokens near [';'].",
    "caused_by": {
      "type": "no_viable_alt_exception",
      "reason": null
    }
  }

如果我删除 return 关键字，那么脚本会运行，但我会得到预期的错误行为。我可以通过使用布尔值来跟踪电子邮件删除来纠正这种行为，但为什么我不能早点返回？

4

1 回答 1

1

很难说，您可以通过将 lambda 比较器传递给retainAll或removeIf 

ctx._source.managers.removeIf(m -> m.email.equals(params.managerEmail))

Lambda 表达式和方法引用与Java 的.

于 2018-06-26T04:35:35.437 回答