我不确定这是不是完美的方法,但这对我有用,而且似乎并不太复杂:
ramdanDate = ramdanDate.with(ChronoField.YEAR, ramdanDate.get(ChronoField.YEAR) - 1);
在转换为代码之前插入此行,LocalDate
现在将打印:
Ramdan 2017
2017-05-27
2017-06-24
编辑:
假设即使(如果你的公历年份与斋月的两个实例重叠,找到两者)是需要的......我想不出一种实现它的方法。你能建议吗?
将舌头伸直放在嘴里:
public static void printRamdanDates(int gregorianYear) {
LocalDate gregDate = LocalDate.ofYearDay(gregorianYear, 1);
HijrahDate ramdanDate = HijrahDate.from(gregDate)
.with(ChronoField.DAY_OF_MONTH, 1)
.with(ChronoField.MONTH_OF_YEAR, 9);
LocalDate ramdanStart = LocalDate.from(ramdanDate);
LocalDate ramdanEnd = LocalDate.from(ramdanDate.with(TemporalAdjusters.lastDayOfMonth()));
// if in previous Gregorian year, skip
while (ramdanEnd.getYear() < gregorianYear) {
ramdanDate = ramdanDate.with(ChronoField.YEAR, ramdanDate.get(ChronoField.YEAR) + 1);
ramdanStart = LocalDate.from(ramdanEnd);
ramdanEnd = LocalDate.from(ramdanDate.with(TemporalAdjusters.lastDayOfMonth()));
}
if (ramdanStart.getYear() > gregorianYear) { // in following Gregorian year
System.out.println("No Ramdan in " + gregorianYear);
} else {
System.out.println("Ramdan " + gregorianYear);
do {
System.out.println(ramdanStart);
System.out.println(ramdanEnd);
ramdanDate = ramdanDate.with(ChronoField.YEAR, ramdanDate.get(ChronoField.YEAR) + 1);
ramdanStart = LocalDate.from(ramdanDate);
ramdanEnd = LocalDate.from(ramdanDate.with(TemporalAdjusters.lastDayOfMonth()));
} while (ramdanStart.getYear() == gregorianYear);
}
}
如果我将 2017 年提供给上述方法,它会给出与以前相同的结果:
printRamdanDates(2017);
输出:
Ramdan 2017
2017-05-27
2017-06-24
但是,请尝试例如 2000 年或 2030 年,当斋月在公历/ISO 年发生两次时。
printRamdanDates(2000);
printRamdanDates(2030);
输出:
Ramdan 2000
1999-12-09
2000-01-07
2000-11-27
2000-12-26
Ramdan 2030
2030-01-05
2030-02-03
2030-12-26
2031-01-23