2

这是示例查询-

WITH empdata AS (SELECT xmltype ('<office>
                            <emp>
                                <empno>1</empno>
                                <ename>Abraham</ename>
                                <deptno>10</deptno>
                            </emp>
                            <emp>
                                <empno>2</empno>
                                <ename>Alexander</ename>
                                <deptno>10</deptno>
                            </emp>
                            <emp>
                                <empno>3</empno>
                                <ename>Benjamin</ename>
                                <deptno>20</deptno>
                            </emp>
                            <emp>
                                <empno>4</empno>
                                <ename>Bradley</ename>
                                <deptno>20</deptno>
                            </emp>
                         </office>') AS xcol FROM dual),
     dept AS
         (SELECT 10 deptno, 'Accounting' dname FROM dual
          UNION ALL
          SELECT 20, 'Broking' FROM dual
          UNION ALL
          SELECT 30, 'HR' FROM dual)
SELECT d.dname, e.ename, e.empno
  FROM dept d
       CROSS JOIN empdata e_data
       LEFT OUTER JOIN
       xmltable (
           'office/emp'
           PASSING e_data.xcol
           COLUMNS deptno NUMBER (28, 0) PATH 'deptno',
                   ename VARCHAR2 (10) PATH 'ename',
                   empno NUMBER (28, 0) PATH 'empno') e
           ON d.deptno = e.deptno;

结果我得到-

DNAME      ENAME           EMPNO
---------- ---------- ----------
Accounting Abraham             1
Accounting Alexander           2
Broking    Benjamin            3
Broking    Bradley             4

为什么结果集中没有显示第三行dept，即 HR 的第三行？理想情况下，根据 LEFT JOIN 规则，左侧表中的所有记录都应显示。为什么那个被过滤掉了？

4

1 回答 1

2

你有外部连接和交叉连接错误的方式。empdata您需要作为子节点进行交叉连接xmltable，并使用该子查询（内联视图）作为外部连接的目标：

...
SELECT d.dname, e.ename, e.empno
  FROM dept d
       LEFT OUTER JOIN
       (
         SELECT x.*
          FROM empdata e_data
               CROSS JOIN 
               xmltable (
                   'office/emp'
                   PASSING e_data.xcol
                   COLUMNS deptno NUMBER (28, 0) PATH 'deptno',
                           ename VARCHAR2 (10) PATH 'ename',
                           empno NUMBER (28, 0) PATH 'empno') x
        ) e
           ON d.deptno = e.deptno;

DNAME      ENAME           EMPNO
---------- ---------- ----------
Accounting Abraham             1
Accounting Alexander           2
Broking    Benjamin            3
Broking    Bradley             4
HR
于 2018-06-21T12:24:22.533 回答