沿着圆的周长绘制均匀分布的点的一种简单方法是将整个圆分成相等的小角度,从中获得从圆心到所有点的角度。然后,可以计算每个点的坐标 (x,y)。这是执行该任务的代码:
import matplotlib.pyplot as plt
import numpy as np
fig = plt.figure(figsize=(8, 8))
n_dots = 120 # set number of dots
angs = np.linspace(0, 2*np.pi, n_dots) # angles to the dots
cx, cy = (50, 20) # center of circle
xs, ys = [], [] # for coordinates of points to plot
ra = 20.0 # radius of circle
for ang in angs:
# compute (x,y) for each point
x = cx + ra*np.cos(ang)
y = cy + ra*np.sin(ang)
xs.append(x) # collect x
ys.append(y) # collect y
plt.scatter(xs, ys, c = 'red', s=5) # plot points
plt.show()
结果图:
或者,可以使用 numpy 的广播性质并缩短代码:
import matplotlib.pyplot as plt
import numpy as np
fig=plt.figure(figsize=(8, 8))
n_dots = 120 # set number of dots
angs = np.linspace(0, 2*np.pi, n_dots) # angles to the dots
cx, cy = (50, 20) # center of circle
ra = 20.0 # radius of circle
# with numpy's broadcasting feature...
# no need to do loop computation as in above version
xs = cx + ra*np.cos(angs)
ys = cy + ra*np.sin(angs)
plt.scatter(xs, ys, c = 'red', s=5) # plot points
plt.show()