2

我试图创建一个客户端服务器 web api，其中客户端调用 web 服务，比如 web1，然后 web1 成为另一个 web 服务的客户端，比如 web2。web2 返回到 web1，因此客户端执行。我的目标是创建一个 Web 服务组合并将结果打印为两个 Web 服务的提交。

在这样做时我遇到了这个错误：

line 1:0 no viable alternative at character 'H' 
line 1:1 no viable alternative at character 'e' 
line 1:2 no viable alternative at character 'l'
line 1:3 no viable alternative at character 'l'
line 1:4 no viable alternative at character 'o'
line 1:5 no viable alternative at character 'p'
line 1:6 no viable alternative at character 'r'
line 1:7 no viable alternative at character 'i'
line 1:8 no viable alternative at character 'y'
line 1:9 no viable alternative at character 'a'
line 0:-1 no viable alternative at input '<EOF>'
Exception in thread "main" javax.ws.rs.WebApplicationException: HTTP 400 Bad 
Request

这里 'hello' 是我调用getMessage()时应该运行的消息，而 'priya' 是在getName()上调用的名称

代码是：

//客户

public class MessageClient {
public static void main(String[] args) {

    Client client= ClientBuilder.newClient();
    WebTarget baseTarget = 
    client.target("http://localhost:8080/messenger/webapi");
    WebTarget messageTarget = baseTarget.path("messages");
    WebTarget singleMsgTarget = messageTarget.path("{messageId}");

    Message message1= singleMsgTarget
            .resolveTemplate("messageId", "1")
            .request()
            .get(Message.class);

    System.out.println(message1.getMessage());
}
}

//web1（这是web2的客户端）

 @Path("/messages")
public class MessageResources {
MessageService ms = new MessageService();

@GET
@Path("{messageId}")
@Produces(MediaType.APPLICATION_JSON)
public String getMessage(@PathParam("messageId") long id)
{

Client client= ClientBuilder.newClient();

    WebTarget baseTarget= 
client.target("http://localhost:8080/messenger/webapi");
    WebTarget infoTarget= baseTarget.path("/info");
    WebTarget singleInfoTarget= infoTarget.path("{infoId}");

    InfoCreated info= singleInfoTarget
            .resolveTemplate("infoId", "1")
            .request()
            .get(InfoCreated.class);
    String name = info.getName();

    Message message = ms.getMessage(id);

    String msg=message.getMessage();

    String result = msg.concat(name);

    return result;
}

代码中没有错误，但是在运行时出现错误。

4

0 回答 0