1

我正在尝试使用“twitter”npm 包将视频媒体上传和发布到 twitter。

在此期间，我面临一个错误：

error  Error: HTTP Error: 400 Bad Request
at Request._callback (/Volumes/Office/Work/Pack3/developer/tweet-it/node_modules/twitter/lib/twitter.js:221:9)
at Request.self.callback (/Volumes/Office/Work/Pack3/developer/tweet-it/node_modules/request/request.js:185:22)
at Request.emit (events.js:180:13)
at Request.<anonymous> (/Volumes/Office/Work/Pack3/developer/tweet-it/node_modules/request/request.js:1157:10)
at Request.emit (events.js:180:13)
at IncomingMessage.<anonymous> (/Volumes/Office/Work/Pack3/developer/tweet-it/node_modules/request/request.js:1079:12)
at Object.onceWrapper (events.js:272:13)
at IncomingMessage.emit (events.js:185:15)
at endReadableNT (_stream_readable.js:1101:12)
at process._tickCallback (internal/process/next_tick.js:114:19)

代码库初始化库

var Twitter = require('twitter');

所有详细信息都通过 Twitter 应用程序控制台生成。

var twitterClient = new Twitter({
    consumer_key: process.env.TWITTER_CONSUMER_KEY,
    consumer_secret: process.env.TWITTER_CONSUMER_SECRET,
    access_token_key: process.env.TWITTER_ACCESS_TOKEN_KEY,
    access_token_secret: process.env.TWITTER_ACCESS_TOKEN_SECRET
});


function makePost(endpoint, params) {
        return new Promise(function (resolve, reject) {
            twitterClient.post(endpoint, params, function (error, data, response) {
                if (error) {
                    reject(error);
                } else {
                    resolve(data);
                }
            });
        });
    }

exports.postVideo = async function (req, res, next) {
    var params = req.body;

    const pathToMovie = './medias/video_3_640x360_1mb.mp4';
    const mediaType = 'video/mp4'; // `'video/mp4'` is also supported
    const mediaData = require('fs').readFileSync(pathToMovie);
    const mediaSize = require('fs').statSync(pathToMovie).size;
    console.log('mediaData ', mediaData);

    try {

        var options = {
            command: 'INIT',
            total_bytes: mediaSize,
            media_type: mediaType,
        };

// 这个请求即将完成

        var mediaInit = await makePost('media/upload', options);

        console.log('options ', options);
        console.log('mediaInit ', mediaInit);
        console.log('mediaInit.media_id_string ', mediaInit.media_id_string);

// 此请求无效。

        await makePost('media/upload', {
            command: 'APPEND',
            media_id: mediaInit.media_id_string,
            media: mediaData,
            segment_index: 0
        });

        var mediaFinalize = await makePost('media/upload', {
            command: 'FINALIZE',
            media_id: mediaInit.media_id_string,
        });
        console.log('mediaFinalize ', mediaFinalize);
        var status = {
            status: params.status,
            media_ids: mediaFinalize.media_id_string
        };

        twitterClient.post('statuses/update', status, function (error, tweet, response) {
            if (error) {
                return next(error);
            }
            req.twitterStore = tweet;
            return next();
        });
    } catch (error) {
        console.log('error ', error);
        return next(error);
    }
};

使用的视频： https ://www.sample-videos.com/video/mp4/360/big_buck_bunny_360p_1mb.mp4

参考：https ://github.com/desmondmorris/node-twitter/tree/master/examples#chunked-media

4

1 回答 1

-1

在示例中包含上传媒体的三个命令：

  1. 在里面
  2. 附加
  3. 完成

INIT 和 APPEND 命令在您的代码中似乎是正确的，但在 FINALIZE 命令中输入了 media_id。如果我没有误解代码，您应该使用“mediaInit”对象而不是“media_id_string”来设置此参数。

  /**
   * Step 2 of 3: Append file chunk
   * @param String mediaId    Reference to media object being uploaded
   * @return Promise resolving to String mediaId (for chaining)
   */
  function appendUpload (mediaId) {
    return makePost('media/upload', {
      command      : 'APPEND',
      media_id     : mediaId,
      media        : mediaData,
      segment_index: 0
    }).then(data => mediaId);
  }

第二步返回 mediaId，该对象在第三步中使用：

  /**
   * Step 3 of 3: Finalize upload
   * @param String mediaId   Reference to media
   * @return Promise resolving to mediaId (for chaining)
   */
  function finalizeUpload (mediaId) {
    return makePost('media/upload', {
      command : 'FINALIZE',
      media_id: mediaId  <-------------
    }).then(data => mediaId);
  }

但是在您的代码中，您将“mediaInit.media_id_string”作为参数 media_id 的值传递：

var mediaFinalize = await makePost('media/upload', {
    command: 'FINALIZE',
    media_id: mediaInit.media_id_string, <-------------
});

可能这是您的代码中的错误。

于 2018-06-06T08:02:05.657 回答