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I have a column that has values of length 5,6,8, or 9. The column should just have values of length 6 or 9. I need to add leading 0's if the value is of length 5 or 8.

There is another column which can identfy if the value should be 6 or 9 digits (indicator). An indicator value of 'Red' means 6 digits, and an indicator of 'Green' means 9 digits. 

df['digits'] = df[df['indicator'] == 'red']['digits'].apply(lambda x: "{:006d}".format(x))
df['digits'] = df[df['indicator'] == 'green']['digits'].apply(lambda x: "{:009d}".format(x))


id    indicator     digits
0     red           54324
1     red           654345
2     green         533345678
3     green         56438594

expected result:

id    indicator     digits
0     red           054324  # 0 added to this value
1     red           654345
2     green         533345678
3     green         056438594 # 0 added to this value

I am getting an error of ValueError: Unknown format code 'd' for object of type 'float'. Any ideas why? What did I miss?

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1 回答 1

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The error message tells you the type of your digits column is float, you need to change it to int.

Also, lambda x: "{:006d}".format(x) is just "{:006d}".format:

df['digits'] = df[df['indicator'] == 'red']['digits'].astype(int).apply("{:006d}".format)
于 2018-06-02T16:25:48.293 回答