0

我需要动态生成 html 表并在下面列出 driver_id。它类似于枢轴，但问题是 zone_name 可以每天更改。我正在使用 jquery 和 linq.js。

到目前为止我已经尝试过：

var data =
            [
                {
                    "ColorCode": "green",
                    "StatusName": "ACTIVE",
                    "rankId": 0,
                    "zone_name": "Zone A",
                    "driver_id": 100,
                    "zone_rank": 1,
                    "status_id": null,
                    "company_id": null,
                    "updated_on": null,
                    "Driver": null,
                    "login_status": null
                },
                {
                    "ColorCode": "yellow",
                    "StatusName": "BREAK",
                    "rankId": 0,
                    "zone_name": "Zone B",
                    "driver_id": 101,
                    "zone_rank": 1,
                    "status_id": null,
                    "company_id": null,
                    "updated_on": null,
                    "Driver": null,
                    "login_status": null
                },
                {
                    "ColorCode": "green",
                    "StatusName": "ACTIVE",
                    "rankId": 0,
                    "zone_name": "Zone A",
                    "driver_id": 102,
                    "zone_rank": 4,
                    "status_id": null,
                    "company_id": null,
                    "updated_on": null,
                    "Driver": null,
                    "login_status": null
                }
            ]

    var zTable = document.getElementById('tblZoneRank');
    var allzones = Enumerable.From(data)
                             .Distinct(p => p.zone_name)
                             .Select(p => p.zone_name).ToArray();

    $.each(allzones, function (i, item) {
    var tr = document.createElement('tr');
    var td = document.createElement("td");
    var txt = document.createTextNode(item);

    td.appendChild(txt);
    tr.appendChild(td);
    var childItem = Enumerable.From(data)
                              .Where(p => p.zone_name == item)
                              .ToArray();
    $.each(childItem, function (j, citem) {
        var ctd = document.createElement("td");
        var ctxt = document.createTextNode(citem.driver_id);

        ctd.appendChild(ctxt);
        $(ctd).css('background-color', citem.ColorCode);
        tr.appendChild(ctd);
    });
    zTable.appendChild(tr);
});

它以这种方式给我输出：

<table id="tblZoneRank">
  <tr>
    <td>Zone A</td>
    <td style="background-color: rgb(0, 128, 0);">100</td>
    <td style="background-color: rgb(0, 128, 0);">102</td>
 </tr>
 <tr>
    <td>Zone B</td>
    <td style="background-color: rgb(255, 255, 0);">101</td>
 </tr>
</table>

在此处输入图像描述

但我需要以这种格式输出：它应该将 zone_name 显示为列名，并在 driver_id 下方显示，第一个 id 应该是 zone_rank 1 和 2，依此类推.. 在此处输入图像描述

4

2 回答 2

1

因此，根据我从您的问题中收集到的信息，您正在尝试按区域对数据项进行分组，然后将它们输出到列是区域的表中。Linq.js 可以很好地处理这个问题，只是在将数据行转换为列时会遇到一些问题。

const zTable = $('#tblZoneRank');
const rows = Enumerable.From(data)
  .GroupBy(p => p.zone_name, p =>
    $('<td></td>')
      .css({'background-color': p.ColorCode})
      .text(p.driver_id)
  )
  .Let(buildRows)
  .Select(rs =>
    $('<tr></tr>').append(rs)
  );
rows.ForEach(r => r.appendTo(zTable));

function buildRows(gs) {
  const header = gs.Select(g =>
    $('<th></th>').text(g.Key())
  ).ToArray();
  const rows = Enumerable.RepeatWithFinalize(
      () => gs.Select(g => g.GetEnumerator()).ToArray(),
      es => es.forEach(e => e.Dispose())
    )
    .Select(es => es.map(e => [e.MoveNext(), e.Current()]))
    .TakeWhile(xs => xs.reduce((a, x) => a || x[0], false))
    .Select(xs => xs.map(x => x[0] ? x[1] : $('<td></td>')));
  return Enumerable.Return(header).Concat(rows);
}
于 2019-02-15T00:12:36.950 回答
0

不熟悉 linq.js，所以我使用原生数组方法Array#reduce()和Map对象来创建唯一区域

const $table = $('#zoneTable');

// creates Map object with zone names as keys and arrays of jQuery objects(cells) as values
const zoneMap = data.reduce((map, item) => {
  const col = map.get(item.zone_name) || [createCell(item.zone_name)];
  col.push(createCell(item.driver_id, item.ColorCode));
  return map.set(item.zone_name, col);
}, new Map());

// convert Map values to array of arrays. Each sub array is a table column
const colCells = [...zoneMap.values()];

const totalRows = Math.max(...colCells.map(e => e.length));

for (let i = 0; i < totalRows; i++) {
  const rowCells = colCells.map(col => col[i] || createCell());// fill any missing with empty cell
  const $row = $('<tr>').append(rowCells);
  $table.append($row)
}

// helper function to create cells
function createCell(text = '', color = null) {
  const $td = $('<td>').text(text);
  return color ? $td.css('background-color', color) : $td;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<table id="zoneTable"></table>


<script>
  var data = [{
      "ColorCode": "green",
      "StatusName": "ACTIVE",
      "rankId": 0,
      "zone_name": "Zone A",
      "driver_id": 100,
      "zone_rank": 1,
      "status_id": null,
      "company_id": null,
      "updated_on": null,
      "Driver": null,
      "login_status": null
    },
    {
      "ColorCode": "yellow",
      "StatusName": "BREAK",
      "rankId": 0,
      "zone_name": "Zone B",
      "driver_id": 101,
      "zone_rank": 1,
      "status_id": null,
      "company_id": null,
      "updated_on": null,
      "Driver": null,
      "login_status": null
    },
    {
      "ColorCode": "green",
      "StatusName": "ACTIVE",
      "rankId": 0,
      "zone_name": "Zone A",
      "driver_id": 102,
      "zone_rank": 4,
      "status_id": null,
      "company_id": null,
      "updated_on": null,
      "Driver": null,
      "login_status": null
    }
  ]
</script>

于 2018-05-27T20:42:08.167 回答