2

我有一个如下表：

Region    Country    Manufacturer    Brand    Period    Spend
R1        C1         M1              B1       2016      5
R1        C1         M1              B1       2017      10
R1        C1         M1              B1       2017      20
R1        C1         M1              B2       2016      15
R1        C1         M1              B3       2017      20
R1        C2         M1              B1       2017      5
R1        C2         M2              B4       2017      25
R1        C2         M2              B5       2017      30
R2        C3         M1              B1       2017      35
R2        C3         M2              B4       2017      40
R2        C3         M2              B5       2017      45

我需要找到SUM([Spend]不同的组如下：

  1. 整个表中所有行的总支出
  2. 每个区域的总支出
  3. 每个地区和国家组的总支出
  4. 每个地区、国家和广告客户组的总支出

所以我在下面写了这个查询：

SELECT 
    [Period]
    ,[Region]
    ,[Country]
    ,[Manufacturer]
    ,[Brand]
    ,SUM([Spend]) OVER (PARTITION BY [Period]) AS [SumOfSpendWorld]
    ,SUM([Spend]) OVER (PARTITION BY [Period], [Region]) AS [SumOfSpendRegion]
    ,SUM([Spend]) OVER (PARTITION BY [Period], [Region], [Country]) AS [SumOfSpendCountry]
    ,SUM([Spend]) OVER (PARTITION BY [Period], [Region], [Country], [Manufacturer]) AS [SumOfSpendManufacturer]
FROM myTable

但是对于只有 450K 行的表，该查询需要超过 15 分钟。我想知道是否有任何方法可以优化此性能。提前感谢您的回答/建议！

4

3 回答 3

4

您对问题的描述grouping sets向我表明：

SELECT YEAR([Period]) AS [Period], [Region], [Country], [Manufacturer], 
       SUM([Spend])
GROUP BY GROUPING SETS ( (YEAR([Period]),
                         (YEAR([Period]), [Region]),
                         (YEAR([Period]), [Region], [Country]), 
                         (YEAR([Period]), [Region], [Country], [Manufacturer])
                        );

我不知道这是否会更快，但它似乎更符合您的问题。

于 2018-05-24T19:34:52.320 回答
1

老学校SUM() OVER()：

SELECT 
      [Period]
    , [Region]
    , [Country]
    , [Manufacturer]
    , [Brand]
    , (SELECT SUM([Spend]) FROM myTable t WHERE e.[Period] = t.[Period] GROUP BY [Period]) AS [SumOfSpendWorld]
    , (SELECT SUM([Spend]) FROM myTable t WHERE e.[Period] = t.[Period] AND e.Region = t.Region GROUP BY [Period], [Region] ) AS [SumOfSpendRegion]
    , (SELECT SUM([Spend]) FROM myTable t WHERE e.[Period] = t.[Period] AND e.Region = t.Region AND e.Country = t.Country GROUP BY [Period], [Region], [Country] ) AS [SumOfSpendCountry]
    , (SELECT SUM([Spend]) FROM myTable t WHERE e.[Period] = t.[Period] AND e.Region = t.Region AND e.Country = t.Country AND e.Manufacturer = t.Manufacturer GROUP BY [Period], [Region], [Country], [Manufacturer] ) AS [SumOfSpendManufacturer]
FROM myTable e

虽然这不是优雅的方式，但它可以完成工作。我强烈建议您查看表格并对其进行分析，以了解哪些替代方法最适合您的情况。如果您觉得这是一条死胡同，那么我建议您使用临时表来加快速度。例如，您可以根据句点选择行并使用批量复制将它们直接插入临时表，然后发挥您的作用。我见过迫使我使用临时表而不是简单的选择查询的表。其他人强迫我将桌子扩展成两张桌子。

所以，它并不总是干净整洁！

我希望这会给您提供另一种见解，对您的旅程有所帮助。

于 2018-05-24T21:04:30.987 回答
1

在此处使用 cross apply 来加快查询速度：

 SELECT 
     periodyear
    ,[Region]
    ,[Country]
    ,[Manufacturer]
    ,[Brand]
    ,SUM([Spend]) OVER (PARTITION BY  periodyear AS [SumOfSpendWorld]
    ,SUM([Spend]) OVER (PARTITION BY  periodyear, [Region]) AS [SumOfSpendRegion]
    ,SUM([Spend]) OVER (PARTITION BY  periodyear, [Region], [Country]) AS [SumOfSpendCountry]
    ,SUM([Spend]) OVER (PARTITION BY  periodyear, [Region], [Country], [Manufacturer]) AS [SumOfSpendManufacturer]
FROM myTable
  cross apply (select YEAR([Period]) periodyear) a
于 2018-05-24T19:33:28.633 回答