0

我有一个没有主键并且按日期分区的表；像这样的列：

1. user_id  
2. device
3. region
4. datetime
5. and other columns

它包含来自网站游戏的用户生成事件，它们每秒触发一次。我想返回一个批次，其中包含当天前 6 个用户（表格顶部）生成的所有事件（包括重复行），用于检查条件：

地区 = 美国

- one user from iOS
- one user from android
- one user from PC

地区 = 欧盟

- one user from iOS
- one user from android
- one user from PC

你能提供一个我应该从哪里开始的示例代码吗？我的一个朋友提出了一些关于 RANK() 的建议，但我从未使用过它。

谢谢 ！

SELECT * FROM 
    (SELECT user_id, 
    event_post_time, 
    device, 
    region, 
    COUNT(DISTINCT player_id) over (partition by player_id) as ct_pid, 
    COUNT(DISTINCT region) over (partition by region) as ct_region, 
    COUNT(DISTINCT device) over (partition by device) as ct_device 
    FROM events 
    WHERE event_post_time = current_date() 
    AND region IN ('EU','US') 
    AND device IN ('ios','android','pc')) e 
WHERE ct_pid <= 6 
AND ct_region <= 2 
AND ct_device <= 3 
ORDER BY player_id

在SQLFiddle 和预期输出中添加虚拟数据：

user_id device region date_generated

  1  ios  EU  22-05-18
  1  ios  EU  22-05-18
  1  ios  EU  22-05-18
  4  ios  US  22-05-18
  4  ios  US  22-05-18
  2  android  EU  22-05-18
  2  android  US  22-05-18
  4  pc  EU  22-05-18
  4  pc  EU  22-05-18
  4  pc  EU  22-05-18
  5  pc  US  22-05-18
4

1 回答 1

0

可能，这就是您正在寻找的。

select * from (
select rank() over (partition by region,device order by cn desc) as
top_num,player_id, region,device,cn from 
(
select count(*) as cn , player_id,region,device from 
test_table group by player_id,region,device 
)l
)t 
where top_num = 1;

让我知道这是否有帮助。

OP 编辑​​：我设法使用您提供的查询使其适用于我想要的；这是最后一个

WITH combo 
 AS (SELECT user_id, 
            region, 
            device 
     FROM   (SELECT Rank() 
                      OVER ( 
                        partition BY region, device 
                        ORDER BY cn DESC) AS top_num, 
                    user_id, 
                    region, 
                    device, 
                    cn 
             FROM   (SELECT Count(*) AS cn, 
                            user_id, 
                            region, 
                            device 
                     FROM   samples 
                     GROUP  BY user_id, 
                               region, 
                               device)l)t 
     WHERE  top_num = 1) 
SELECT s.user_id, 
   s.region, 
   s.device 
FROM   samples s 
   JOIN combo 
     ON s.user_id = combo.user_id 
        AND s.region = combo.region 
        AND s.device = combo.device
于 2018-05-22T16:34:47.587 回答